我假装将std::vector
std::complex<float>
存储在二进制文件中,然后再将该数据加载到std :: vector中。我在SO中检查了类似的问题,并提出了以下代码:
#include <complex>
#include <iostream>
#include <memory>
#include <fstream>
#include <iterator>
#include <random>
#include <vector>
using namespace std;
typedef vector<complex<float>> complex_vector;
float get_random(){
static std::default_random_engine e;
static std::uniform_real_distribution<> dis(-10, 10);
return dis(e);
}
int main(){
// Random number generator
srand(static_cast<unsigned> (time(0)));
// Create a vector with 25 random complex<float> values
std::shared_ptr<vector<complex<float>>> buffer = std::make_shared<vector<complex<float>>>();
for(unsigned int i=0; i<25; i++){
buffer->push_back(complex<float>(get_random(), get_random()));
}
// Write those values into a binary file
std::string binFileName = "aux.bin";
std::ofstream rawFile(binFileName, std::ios::binary);
for(unsigned int i=0; i<buffer->size(); i++){
rawFile.write(reinterpret_cast<const char*>(&buffer->at(i)), sizeof(complex<float>));
}
rawFile.close();
// Load the binary file into the buffer
std::ifstream input(binFileName, std::ios::binary);
complex_vector auxBuffer{std::istream_iterator<complex<float>>(input), std::istream_iterator<complex<float>>()};
unsigned int samplesRead = auxBuffer.size();
std::cout << samplesRead;
return 0;
}
输出:
0
我错过了什么?
编辑: 在NathanOliver的回答之后,这就是我的代码现在的样子:
#include <complex>
#include <iostream>
#include <memory>
#include <fstream>
#include <iterator>
#include <random>
#include <vector>
using namespace std;
typedef vector<complex<float>> complex_vector;
float get_random(){
static std::default_random_engine e;
static std::uniform_real_distribution<> dis(-10, 10);
return dis(e);
}
int main(){
// Random number generator
srand(static_cast<unsigned> (time(0)));
// Create a vector with 25 random complex<float> values
std::shared_ptr<complex_vector> buffer = std::make_shared<complex_vector>();
for(unsigned int i=0; i<25; i++){
buffer->push_back(complex<float>(get_random(), get_random()));
}
// Write those values into a binary file
std::string binFileName = "aux.bin";
std::ofstream rawFile(binFileName, std::ios::binary);
rawFile.write(reinterpret_cast<const char*>(buffer->size()), sizeof(buffer->size()));
rawFile.write(reinterpret_cast<const char*>(buffer->data()), sizeof(std::complex<float>) * buffer->size());
rawFile.close();
// Load the binary file into the buffer
std::ifstream input(binFileName, std::ios::binary);
complex_vector::size_type nSamples;
input.read(reinterpret_cast<char*>(nSamples), sizeof(complex_vector::size_type));
std::cout << nSamples;
complex_vector *destination = new complex_vector(25);
input.read(reinterpret_cast<char*>(destination->data()), sizeof(std::complex<float>) * nSamples);
return 0;
}
我在第一次写函数调用时得到了一个SIGSEGV。
另外,我不明白为什么写作,但我必须阅读。
答案 0 :(得分:1)
您无法将二进制写入与格式化读取混合,这正是您现在正在做的事情。即使文件以二进制模式打开
complex_vector auxBuffer{std::istream_iterator<complex<float>>(input), std::istream_iterator<complex<float>>()};
调用运算符&gt;&gt; of
复杂&gt; and not
读which is what you should use if you write the data with
写`。
您有两种方法可以解决这个问题。您可以执行格式化写入而不是像
这样的二进制for (const auto& e : *buffer)
rawFile << e << "\n"; // or space or any other white space delimiter
然后你会完全按照你的意思阅读它。
你的另一个选择是write
向量的大小和向量的内容,然后read
那些都回来了
// write the size of the vector
rawFile.write(reinterpret_cast<const char*>(&buffer->size()), sizeof(buffer->size()));
// write the whole contents of the vector in one go
rawFile.write(reinterpret_cast<const char*>(buffer->data()), sizeof(std::complex<float>) * buffer->size());
// and then to read it back in we get the size
complex_vector::size_type size;
input.read(reinterpret_cast<char*>(&size), sizeof(size));
// construct a vector of that size
complex_vector auxBuffer(size);
// and then read the data back into the vector
input.read(reinterpret_cast<char*>(auxBuffer.data()), sizeof(std::complex<float>) * auxBuffer->size());
我个人喜欢第一个选项,因为它看起来更干净但如果这对性能敏感,那么二进制模式通常会更快。