Question

对于管理员我执行某种类型的SQL操作。记录属于以下类型。

date        number of failed login
13/02/2017            1
12/02/2017            2
11/02/2017            0
10/02/2017            9
09/02/2017            0

我希望单行中的0,9,0,2,1。

我尝试过以下查询。但默认情况下未能获得零。用户必须在哪个用户日执行零操作。

select LISTAGG(cnt, ', ') 
from (select count(*) as cnt 
      from OPERATIONINFO 
      where OPERATIONTYPE='FAILEDLOGIN' 
        and CUSTID = 123 
        and date(UPDATEDDATEOFLOGIN) > (current date - 5 day)  
      group by YEAR(date), MONTH(date), DAY(date)

请帮忙。

Answer 1

您需要使用解码来转动数据。看看这个带有这个

的例子

INSERT INTO Sales VALUES
(2004, 1, 20),
(2004, 2, 30),
(2004, 3, 15),
(2004, 4, 10),
(2005, 1, 18),
(2005, 2, 40),
(2005, 3, 12),
(2005, 4, 27);

到这个

Year Q1 Q2 Q3 Q4
---- -- -- -- --
2004 20 30 15 10
2005 18 40 12 27

by using decode in db2

SELECT Year,
       MAX(DECODE(Quarter, 1, Results)) AS Q1,
       MAX(DECODE(Quarter, 2, Results)) AS Q2,            
       MAX(DECODE(Quarter, 3, Results)) AS Q3,
       MAX(DECODE(Quarter, 4, Results)) AS Q4
  FROM Sales
  GROUP BY Year;

Answer 2

你需要一个日期表......我在这里使用递归动态制作 - 不是最好的方式......

WITH DATES_TABLE AS 
(
   SELECT CURRENT DATE - 5 DAYS AS D FROM SYSIBM.SYSDUMMY1

   UNION ALL

   SELECT D + 1 DAY AS D FROM DATES_TABLE WHERE D < CURRENT DATE
), THE_DATA AS
(
  select D.D, SUM(CASE WHEN O.UPDATEDDATEOFLOGIN IS NOT NULL THEN 1 ELSE 0 END) as cnt 
  from DATES_TABLE D
  LEFT JOIN OPERATIONINFO O ON O.UPDATEDDATEOFLOGIN = D.D
  where O.OPERATIONTYPE='FAILEDLOGIN' 
    and O.CUSTID = 123 
  group by D.D

)
select  LISTAGG(cnt, ', ') 
from THE_DATA

如何通过日期的SQL语句在DB2中显示最近5天的审计记录，并在一行中显示它们的日期计数

2 个答案: