我使用自定义服务定义了一个JavaScript函数,我使用控制器中的服务调用了此函数。这个函数使用两个参数:第一个是我通过点击下面的API获得的输入,第二个是我使用ng-model
指令得到的年份的值。当我在控制器中调用此函数时,我收到类似type is not defined
或id is not defined
等错误。是否是在控制器中调用JavaScript函数的正确方法。请建议我。
$http.get("http://152.144.218.70:8080/USACrime/api/crimeMultiple?city=" +$scope.strCity + "&crime=" + $scope.type1 + "&model=" + model).success(function (result) {
$scope.prograssing = false;
console.log("manisha", $scope.strCity);
console.log("kanika", result);
$scope.output = result;
console.log("monga", $scope.output);
$scope.hex = hexafy.year_city($scope.output,$scope.type);
console.log("service", $scope.hex);
});
myapp.js
var app= angular.module("myApp",["ngRoute","leaflet-directive","pb.ds.components"]);
var geomarker = new L.FeatureGroup();
app.service('hexafy', function() {
this.year_city = function (input2,years) {
if(years.toLowerCase()=="all"){
years = "2012,2013,2014,2015,2016,2017,2018,2019";
}
var yrs = years.split(",");
output = {};
outerBoundary = {};
boundary = {};
boundary["boundaryId"] = input[0]["id"];
boundary["boundaryType"] = input[0]["type"];
boundary["boundaryRef"] = "C1";
outerBoundary["boundary"] = boundary;
output["boundaries"] =outerBoundary;
themes = [];
for(var i in input){
crimeTheme = {};
crimeThemeValue = {};
crimeThemeValue["boundaryRef"] = "C1";
result = [];
for(var j in input[i]["prediction"]){
dict = {};
if(yrs.indexOf(input[i]["prediction"][j]["year"])>-1){
dict["name"] = input[i]["prediction"][j]["year"]+" "+input[i]["crime"]+" Crime";
dict["description"] = input[i]["crime"]+" Crime for "+input[i]["prediction"][j]["year"];
dict["value"] = input[i]["prediction"][j]["count"];
dict["accuracy"] = input[i]["accuracy"];
result.push(dict);
}
}
crime = input[i]["crime"].toLowerCase()+"CrimeTheme";
crimeThemeValue["individualValueVariable"] = result;
console.log('crimeThemeValue["individualValueVariable"]',crimeThemeValue["individualValueVariable"]);
crimeTheme[crime] = crimeThemeValue;
themes.push(crimeTheme);
console.log("themes",JSON.stringify(themes));
}
output["themes"] = themes;
console.log(output);
return output;
};
});
});
答案 0 :(得分:0)
1){@ 1}}和.success
方法已被弃用,并不适合使用它。相反,你最好使用.error
2)要使用服务方法,正确的方法是这样:
.then(successCallback, errorCallback)
所以在你的情况下,走的路是:
app.service('myService', function() {
var service = {
method:method
};
return service;
function method() {
//Logic
}
})