Question

在socket.io中，断开连接时是否需要手动拨打socket.leave()？或NodeJs Socket.io本身处理它？</ p>

socket.on("disconnect" function() {
   this.leave("room"); // is this necessary?
});

Answer 1

否，所有房间在发出此事件之前已经离开。

Code from socket.io：

Socket.prototype.onclose = function(reason){
  if (!this.connected) return this;
  debug('closing socket - reason %s', reason);
  this.emit('disconnecting', reason);
  this.leaveAll();   //leaving all rooms
  this.nsp.remove(this);
  this.client.remove(this);
  this.connected = false;
  this.disconnected = true;
  delete this.nsp.connected[this.id];
  this.emit('disconnect', reason);   //emitting event
};

Answer 2

当断开连接事件时，你不需要手动调用socket.leave（）。有关详细信息，请参阅http://socket.io/docs/rooms-and-namespaces/

它是否需要在Nodejs中断开连接的socket.leave（）

2 个答案: