Question

ab<- as.factor(c("A","B","A","C","B","C","C"))
a123<- as.factor(c(NA,NA,NA,465,NA,532,456))
dd<- as.data.frame(cbind(ab,a123))

这是我拥有的数据框，如果列ab的值为A，我想用0替换NA值，否则NA = 1。

我尝试过以下代码：

dd$Amount[is.Na(dd$Amount)]<- ifelse(my_dd$Activity=="Beneficiary Added", 0,1)

我收到以下错误：

> dd$Amount[is.Na(dd$Amount)]<- ifelse(my_dd$Activity=="Beneficiary Added", 0, 1)
Error in `*tmp*`$Amount : object of type 'closure' is not subsettable

Answer 1

这是我的建议。

abc<- c("A","B","A","C","B","C","C")
df<- data.frame(cbind(abc,a123),stringsAsFactors =FALSE)
df$your_var=ifelse(df$abc %in% "A" & df$a123 %in% NA, 0, ifelse(df$a123 %in% NA,1,df$a123)
print(df)

最佳

帕夫洛

Answer 2

我的评论作为答案加上data.table的例子（我认为语法更加清晰）：

library(data.table)

df <- data.frame(abc = c("A","B","A","C","B","C","C"), a123 = c(NA,NA,NA,465,NA,532,456))
dt <- data.table(df)

# "Classic" data.frame syntax
df$a123[is.na(df$a123)] <- ifelse(df[is.na(df$a123), 'abc'] == "A", 0, 1)
# data.table one
dt[is.na(a123), a123 := ifelse(abc == "A", 0, 1)]

按条件替换NA

2 个答案: