Question

如何编码以共享图库中的当前图像（在imageSwitcher中）。我有一个应用程序，在一个库中有多个图像，然后选择后加载到imageSwitcher。所以现在我想使用共享意图打开共享选项窗口来共享当前正在查看和发送的图像。

这是我的代码： TextView drawableId; TextView stringCopy;

    int imgs[] =
            {
                    R.drawable.pg1,
                    R.drawable.pg2,

            };
    String imgs1[] =
        {
                "R.drawable.pg1",
                "R.drawable.pg2",
        };
    int imgs2[] =
            {
                    R.drawable.infinity_96_58uvb_pg1,
                    R.drawable.infinity_96_58uvb_pg2,

            };

    ImageSwitcher imgSwitcher, imageSwitcher2;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    requestWindowFeature(Window.FEATURE_NO_TITLE);
    setContentView(R.layout.activity_main);
    drawableId = (TextView) findViewById(R.id.textView);
    stringCopy = (TextView) findViewById(R.id.textView2);

    imgSwitcher = (ImageSwitcher) findViewById(imageSwitcher1);
    imgSwitcher.setFactory(this);

    final Gallery gallery = (Gallery) findViewById(R.id.gallery1);
    gallery.setAdapter(new MainActivity.ImageAdapter(this));

    gallery.setOnItemClickListener(new AdapterView.OnItemClickListener() {

        public void onItemClick(AdapterView<?> parent, View v, int position,
                                long id) {
            imgSwitcher.setImageResource(imgs2[position]);
            drawableId.setText(imgs1[position]+"");
            Toast.makeText(MainActivity.this, imgSwitcher + "", Toast.LENGTH_LONG).show();
            imgSwitcher.setVisibility(View.VISIBLE);
        }
    });
    FloatingActionButton fab = (FloatingActionButton) findViewById(R.id.fab);
    fab.setOnClickListener(new View.OnClickListener() {

        public void onClick(View view) {
            postPicture();
        }

        public boolean postPicture() {
            String a = drawableId.getText().toString();
            stringCopy.setText(a);

            Bitmap b = BitmapFactory.decodeFile(a);
            Intent share = new Intent(Intent.ACTION_SEND);
            share.setType("image/*");
            ByteArrayOutputStream bytes = new ByteArrayOutputStream();
            b.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
            File f = new File(Environment.getExternalStorageDirectory() + File.separator + "temporary_file.jpg");
            try {
                f.createNewFile();
                FileOutputStream fo = new FileOutputStream(f);
                fo.write(bytes.toByteArray());
            } catch (IOException e) {
                e.printStackTrace();
            }
            share.putExtra(Intent.EXTRA_STREAM, Uri.parse("file:///sdcard/temporary_file.jpg"));
            startActivity(Intent.createChooser(share, "Share image File"));

            Toast.makeText(MainActivity.this, "clicked", Toast.LENGTH_LONG).show();
            return true;
        }

       });



    }

这是我的错误：

E / BitmapFactory：无法解码流：java.io.FileNotFoundException：R.drawable.pg1：open failed：ENOENT（没有这样的文件或目录） D / AndroidRuntime：关闭VM E / AndroidRuntime：致命异常：主要处理：com.example.mt_br.floatingactionbutton，PID：13647 java.lang.NullPointerException：尝试在空对象引用上调用虚方法'boolean android.graphics.Bitmap.compress（android.graphics.Bitmap $ CompressFormat，int，java.io.OutputStream）' at com.example.mt_br.floatingactionbutton.MainActivity $ 2.postPicture（MainActivity.java:112） at com.example.mt_br.floatingactionbutton.MainActivity $ 2.onClick（MainActivity.java:101）

Answer 1

我取代了这个：

     public boolean postPicture() {

            int Position = gallery.getSelectedItemPosition();
            Bitmap b = BitmapFactory.decodeResource(getResources(), imgs2[Position]);

如何从android中的imageSwitcher分享图像

1 个答案: