Question

这是我的JS函数，它将文本设置为变量。如何分配玩家拥有的神奇宝贝。

function setStats() {
// Sets up stats based on Pokemon
if (computerPokemon === 'Pikachu') {
    var computerAttack = 30;
    var computerUlt = 60; // Does damage
    var computerHealth = 50;
    var computerSpeed = 20;
    var computerAgility = 10;
}

if (playerPokemon === 'Ho-Oh') {
    var playerAttack = 70;
    var playerUlt = 10; // Buffs HP
    var playerHealth = 80;
    var playerSpeed = 35;
    var playerAgility = 12;
}

document.getElementById("pHP").innerHTML = 'Health: ' + playerHealth;
document.getElementById("pSpeed").innerHTML = 'Speed: ' + playerSpeed;
document.getElementById("pAgility").innerHTML = 'Agility: ' + playerAgility; 
}

function startGame() {
// Player Pokemon Selector
var playerPokemonArray = ["Ho-Oh","Venusaur","Weedle"];
var playerPokemonArrayRandom =  Math.floor((Math.random() * playerPokemonArray.length));
var playerPokemon = playerPokemonArray[playerPokemonArrayRandom];
document.getElementById("playerPokemon").innerHTML = 'Your Pokemon is: '     + playerPokemon;

// Computer Pokemon Selector
var computerPokemonArray = ["Pikachu","Charmander","Diglett"];
var computerPokemonArrayRandom =  Math.floor((Math.random() * computerPokemonArray.length));
var computerPokemon = computerPokemonArray[computerPokemonArrayRandom];
document.getElementById("computerPokemon").innerHTML = 'The Computer\'s Pokemon is: ' + computerPokemon;

当我运行此代码时，它会将我的统计信息段落的文本设置为undefined。即使变量的设置取决于他们给出的神奇宝贝。

我尝试过改变我的代码，但没有任何效果。

Answer 1

您的代码正在startGame()函数中设置统计变量，并且您正尝试从setStats()访问它们。 Javascript是一种词法范围的语言。由于您正在使用函数设置变量，因此只有该函数才能访问变量。您可以通过将变量移动到全局范围来解决此问题。

（另外，你永远不会调用函数{{1}}

为什么此代码将文本设置为undefined？

1 个答案: