Question

我尝试使用select ng-options来填充我的下拉菜单。这是我的JSON

{ "Food": [ { "Name": Apple, "HealthCondition": [ { "Name": "High Blood Pressure", "Eat": null }, { "Name": "High Cholesterol", "Eat": null }, { "Name": "Heart Disease", "Eat": null }, { "Name": "Osteoporosis", "Eat": null }, { "Name": "Digestive Disorder", "Eat": null } ] }

这是我的选择<select class="chosen-select" ng-model="selectedValue" ng-options="x.HealthCondition for x in myResults.Food" multiple chosen></select>，我得到的结果是[object Object],[object Object],[object Object],[object Object],[object Object]

我试图获取健康状况名称列表！任何帮助将不胜感激。困了几个小时。我正在使用Angular Chosen指令。如果我只使用像x.Name这样的名称字段，但我想获得HealthCondition名称，这是正常的。

非常感谢任何帮助！

Answer 1

尝试<select class="chosen-select" ng-model="selectedValue" ng-options="x.Name as x.Name for x in myResults.Food.HealthCondition" multiple chosen></select>

Answer 2

问题是您的数据无法用于当前格式的ng-options。您需要将可用的HealthConditions减少为单个数组，而不是将HealthCondition数组作为属性的多个对象。

在您的控制器中，您需要将数据映射到单个数组，如下所示：

$scope.HealthConditions = myResults.reduce(function(arr, result){ 
    for(var i in result.HealthCondition){
        arr.push(result.HealthCondition[i]);
    }
    return arr;
}, []);

然后在您的视图中使用以下内容：

<select class="chosen-select" ng-model="selectedValue" ng-options="x.Name for x in HealthConditions" multiple chosen></select>

Answer 3

一些观察结果：

您的JSON无效。 Apple 应该是 name 键的字符串。
您正在Food中迭代ng-options数组，它应该是HealthCondition。

<强>样本

＆＃13;

var myApp = angular.module('myApp',[]);

myApp.controller('MyCtrl',function($scope) {
    $scope.jsonObj = {
  "Food": [
    {
      "Name": "Apple",
      "HealthCondition": [
        {
        "Name": "High Blood Pressure",
        "Eat": null
        },
        {
        "Name": "High Cholesterol",
        "Eat": null
        },
        {
        "Name": "Heart Disease",
        "Eat": null
        },
        {
        "Name": "Osteoporosis",
        "Eat": null
        },
        {
        "Name": "Digestive Disorder",
        "Eat": null
        }
    ]
}]};
});

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="myApp" ng-controller="MyCtrl">
  <select class="chosen-select" ng-model="selectedValue" ng-options="x.Name as x.Name for x in jsonObj.Food[0].HealthCondition" multiple chosen></select>
</div>

＆＃13;

Angular JS ng-options从JSON中选择列表

3 个答案: