Question

经过几个小时的搜索堆栈并查看类似的问题后，我仍然无法使用它。请帮助指导我！

我要做的就是向我的服务器提交用户名并将其保存在MySQL中 - 只是为了让它正常工作......

我可以将用户名发送到服务器，甚至将硬编码数据返回给iOS模拟器设置标签的文本但是一旦我添加了将数据保存到MySQL的功能，我就会收到错误：“错误域= NSCocoaErrorDomain代码= 3840”字符0周围的值无效。“UserInfo = {NSDebugDescription =字符0周围的值无效。}”

很抱歉奇怪的命名惯例，我偏离了我关注的教程。谢谢！

SWIFT 3：

func Apitest(name: String) {

    let json = ["user" : name]

    do {
        let jsonData = try JSONSerialization.data(withJSONObject: json, options: .prettyPrinted)

        let url = NSURL(string: "I put the actual path here, don't worry")!
        let request = NSMutableURLRequest(url: url as URL)
        request.httpMethod = "POST"

        request.setValue("application/json; charset=utf-8", forHTTPHeaderField: "Content-Type")
        request.httpBody = jsonData

        let task = URLSession.shared.dataTask(with: request as URLRequest){ data, response, error in
            if error != nil{
                print("First Error -> \(error)")
                return
            }
            do {
                let result = try JSONSerialization.jsonObject(with: data!, options: .allowFragments) as? [String:AnyObject]
                print("Result -> \(result!)")

                let label = result?["messages"] as! String

                print(label)

                self.setupLabel(text: label)

            } catch {
                print("Second Error -> \(error)")
            }
        }

        task.resume()
    } catch {
        print(error)
    }
}

API代码（python / flask）

@app.route('/api/get_messages/') methods=['POST'])
def get_messages():
json = request.get_json()

api_test(json['user'])

return jsonify({'messages':json['user']})

MySQL功能：

def api_test(user):
c, conn = connection()
c.execute("INSERT INTO users (email) VALUES (%s)", (user))
conn.commit()
conn.close()
c.close()

Answer 1

从查看代码我会说你的插入命令应该是：

c.execute("INSERT INTO users (email) VALUES (%s)", (user))

向服务器发出post请求时出现Json错误

1 个答案: