Question

我有客户，其用户，其中包含带有多对多表格的调查。所以user_surveys。

我想知道如何深入计算某些关系。我想计算用户对该客户的所有调查

我尝试了什么

Client.php

public function countSurveys()
{
    $employees = $this->employees;

    // this returns Property [surveys] does not exist on this collection instance.
    return $employees->surveys->count();

    // Method whereHas does not exist
    return $employees->whereHas('surveys')->count();
}

这是我的员工方法，它是用户的子集

public function employees()
{
    return $this->users()->whereHas('roles', function ($q) {
        $q->where('name', 'employee');
    });
}

这是用户模型

命名空间App \ Models;

使用App \ LoginToken; 使用Illuminate \ Notifications \ Notifiable; 使用Illuminate \ Foundation \ Auth \ User作为Authenticatable; 使用Spatie \ Permission \ Traits \ HasRoles;

class User extends Authenticatable
{

public function surveys()
{
    return $this->belongsToMany(Survey::class, 'user_surveys', 'user_id', 'survey_id')
        ->withPivot('completed_on', 'status')
        ->withTimestamps();
}

public function journey()
{
    return $this->belongsTo(Scan::class);
}

public function client()
{
    return $this->belongsTo(Client::class);
}

}

可能会迟到，我可能会感到困惑和/或愚蠢。期待您的回复！

Answer 1

另一种方法是

$user = App\User::find(1);
return $user->surveys()->count();

或尝试

$users = App\User::withCount('surveys')->get();
foreach($users as $user) {
    $user->surveys_count;
}

Answer 2

试试这个：

return $this->employees()->withCount('surveys')->get();

Answer 3

在这种情况下没有本机关系。

我创建了HasManyThrough关系，并支持BelongsToMany：Repository on GitHub

安装后，您可以像这样使用它：

class Client extends Model {
    use \Staudenmeir\EloquentHasManyDeep\HasRelationships;

    public function surveys() {
        return $this->hasManyDeep(Survey::class, [User::class, 'user_surveys']);
    }
}

$count = $client->surveys()->count();

Laravel计算多层次关系

我尝试了什么

3 个答案: