我有一个字符串,我想拆分成某些类型的列表。例如,我想将Starter Main Course Dessert
拆分为[Starter, Main Course, Dessert]
我不能使用split(),因为它会拆分Main Course
类型。我怎么能分裂?需要正则表达式吗?
答案 0 :(得分:3)
如果您有可接受的单词列表,则可以使用正则表达式联合:
import re
acceptable_words = ['Starter', 'Main Course', 'Dessert', 'Coffee', 'Aperitif']
pattern = re.compile("("+"|".join(acceptable_words)+")", re.IGNORECASE)
# "(Starter|Main Course|Dessert|Coffee|Aperitif)"
menu = "Starter Main Course NotInTheList dessert"
print pattern.findall(menu)
# ['Starter', 'Main Course', 'dessert']
如果您只想指定应匹配哪些特殊子字符串,可以使用:
acceptable_words = ['Main Course', '\w+']
答案 1 :(得分:0)
我认为指定特殊'更为实际。只有两个单词的代币。
special_words = ['Main Course', 'Something Special']
sentence = 'Starter Main Course Dessert Something Special Date'
words = sentence.split(' ')
for i in range(len(words) - 1):
try:
idx = special_words.index(str(words[i]) + ' ' + words[i+1])
words[i] = special_words[idx]
words[i+1] = None
except ValueError:
pass
words = list(filter(lambda x: x is not None, words))
print(words)