Question

请帮助我，

我发布了2个日期来搜索需要维护并在某个日期离开的车辆，然后将这些结果分成时间范围。我的表看起来像这样：

Ticket          VEhicle         Type            Model           Center          Depart          DateIn                      DateOut
________________________________________________________________________________________________________________________________________________
JBN-115         D113            MOTO BIKE       YBR125          254             403             2017-01-16 16:38:00         2017-01-25 08:54:00
JBN-122         S001            CAR             TYT HILUX       254             410             2017-01-17 08:39:00         2017-01-17 09:39:00
JBN-123         C003            MOTO BIKE       MAX100R         254             403             2017-01-16 09:50:00         2017-01-17 09:41:00
JBN-124         D313            MOTO BIKE       YBR125          254             403             2017-01-16 16:38:00         2017-01-25 08:54:00
JBN-125         S002            CAR             TYT HILUX       254             410             2017-01-17 12:39:00         2017-01-18 14:39:00
JBN-126         C053            MOTO BIKE       MAX100R         254             403             2017-01-16 08:41:00         2017-01-31 09:41:00
JBN-127         D133            MOTO BIKE       YBR125          254             403             2017-01-18 15:38:00         2017-01-25 08:54:00
JBN-128         S008            MOTO BIKE       TYT HILUX       254             410             2017-01-17 13:13:00         2017-01-20 09:24:00
JBN-129         C043            MOTO BIKE       MAX100R         254             403             2017-01-18 08:41:00         2017-01-31 09:41:00
JBN-122         S012            CAR             TYT HILUX       254             410             2017-01-17 08:50:00         2017-01-17 19:39:00
JBN-122         S062            MOTO BIKE       YBR125          254             410             2017-01-17 14:50:00

因此，如果车辆在发布的日期范围内进行维护并且仍未设置维护位置，即使日期Out超过发布日期，它也会显示在结果中。或者如果日期为空白，它仍然会显示，因为它还没有离开这个地方。

所以我正在运行查询以获取2017-01-17和2017-01-18之间的记录

查询应该在您符合标准后查找此车辆：

Ticket          VEhicle         Type            Model           Center          Depart          DateIn                      DateOut
________________________________________________________________________________________________________________________________________________
JBN-122         S001            CAR             TYT HILUX       254             410             2017-01-17 08:39:00         2017-01-17 09:39:00
JBN-122         S012            CAR             TYT HILUX       254             410             2017-01-17 08:50:00         2017-01-17 19:39:00
JBN-125         S002            CAR             TYT HILUX       254             410             2017-01-17 12:39:00         2017-01-18 14:39:00
JBN-128         S008            MOTO BIKE       TYT HILUX       254             410             2017-01-17 13:13:00         2017-01-20 14:24:00
JBN-122         S062            MOTO BIKE       YBR125          254             410             2017-01-17 14:50:00

然后我跳来查看这样的查询输出：

Type        8am     10am    12pm    2pm     4pm
_________________________________________________
CAR         2       1       2       2       2
MOTO BIKE   0       0       1       2       2

我试过这个：

select c.vtype, 
   ( select COUNT(vtype) from Availability where (DATE_FORMAT(DateIn, '%Y-%m-%d %H:%i') < '2017-01-17 00:00' AND DATE_FORMAT(DateOut, '%Y-%m-%d %H:%i') < '2017-01-18 10:00') AND costCente = '254' AND vtype =c.vtype ) as Eight,
   ( select COUNT(vtype) from Availability where (DATE_FORMAT(DateIn, '%Y-%m-%d %H:%i') < '2017-01-17 10:00' AND DATE_FORMAT(DateOut, '%Y-%m-%d %H:%i') < '2017-01-18 12:00') AND  costCente = '254' AND vtype =c.vtype ) as Ten,
   ( select COUNT(vtype) from Availability where (DATE_FORMAT(DateIn, '%Y-%m-%d %H:%i') < '2017-01-17 12:00' AND DATE_FORMAT(DateOut, '%Y-%m-%d %H:%i') < '2017-01-18 14:00') AND  costCente = '254' AND vtype =c.vtype ) as Twelve,
   ( select COUNT(vtype) from Availability where (DATE_FORMAT(DateIn, '%Y-%m-%d %H:%i') < '2017-01-17 14:00' AND DATE_FORMAT(DateOut, '%Y-%m-%d %H:%i') < '2017-01-18 16:00') AND  costCente = '254' AND vtype =c.vtype ) as Tow,
   ( select COUNT(vtype) from Availability where (DATE_FORMAT(DateIn, '%Y-%m-%d %H:%i') < '2017-01-17 16:00' AND DATE_FORMAT(DateOut, '%Y-%m-%d %H:%i') < '2017-01-18 19:00') AND  costCente = '254' AND vtype =c.vtype ) as Four
   from Availability c where costCente = '254' GROUP BY vtype ORDER BY vtype DESC

Answer 1

我不确定你的时间范围是什么条件，例如8am：DateIn＆lt; '2017-01-17 00:00'和DateOut＆lt; '2017-01-18 10:00'，上午8点与此之间没有联系。因此，我认为早上8点是计算在早上0点到早上8点之间仍在维护的车辆的上升时间

SET         @FromTime   = '2017-01-17 00:00:00',
            @ToTime     = '2017-01-18 23:59:59';

SELECT      Type,
            sum(if(DateIn between @FromTime and @FromTime+interval 8 hour,1,0)) as `8am`,
            sum(if(DateIn between @FromTime +interval 8 hour and @FromTime+interval 10 hour,1,0)) as `10am`,
            sum(if(DateIn between @FromTime +interval 10 hour and @FromTime+interval 12 hour,1,0)) as `12am`,
            sum(if(DateIn between @FromTime +interval 12 hour and @FromTime+interval 14 hour,1,0)) as `2pm`,
            sum(if(DateIn between @FromTime +interval 14 hour and @FromTime+interval 16 hour,1,0)) as `4pm`

FROM        Availability

WHERE       costCente = '254'
            AND DateIn >= @FromTime AND if(DateOut = '',DateIn,DateOut) <= @ToTime

GROUP BY    1 
ORDER BY    1 DESC;

您可以根据自己的情况修改条件。

MySQL Query在两个时间戳列之间搜索一系列两个发布日期记录

1 个答案: