Question

我在编写一个以十六进制读取64位无符号长整数的程序时遇到问题，找到最频繁的十六进制数字，并返回它出现的次数以及数字本身。例，输入：0xABCD_FFFF_43FF_42CF 输出：十六进制数字F出现4次

到目前为止，这是我的代码：

#include <stdio.h>
int main()
{
    int i = 0;     
    char count = 0;
    char max = 0;
    char hexDigit = 0;
    unsigned long long x = 0xABCDFFFF43FF42CF;

    for ( i = 0; i < 16; i++)
    {
        if (( x >> i ) & 0xF) // checking bits to see if they match previous hex digit
        {
            count++; // count increases if they are the same
        }
        else
        {
            count = 0;
        }

        if (count > max)
        {
            max = count;
         }
    }

    printf("Hex digit %x occured %d times\n", hexDigit, max);
}

我不确定如何实现找出哪个十六进制数最多，所以任何有关我可以去的方向的帮助都非常感谢。

Answer 1

我相信这应该有效：

#include <stdio.h>
int main()
{
    int i = 0;
    char count = 0;
    char max = 0;
    char hexDigit = -1;
    char answer;
    unsigned long long x = 0xABCDFFFF43FF42CF;

    for ( i = 0; i < 16; i++)
    {
        char curr = (x>>(4*i)) & 0xF;
        if (curr==hexDigit) // checking bits to see if they match previous hex digit
        {
            count++; // count increases if they are the same
        }
        else
        {
            count = 1;
            hexDigit = curr;
        }

        if (count > max)
        {
            max = count;
            answer=hexDigit;
         }
    }

    printf("Hex digit %x occured %d times\n", answer, max);
}

从输入中查找连续十六进制数的最大数量

1 个答案: