这是我将数据发送到表中的代码,工作正常**
<?php
if($_SERVER["REQUEST_METHOD"]=="POST"){
require 'connection.php';
createStudent();
}
function createStudent()
{
global $connect;
$firstname = $_POST["firstname"];
$lastname = $_POST["lastname"];
$age = $_POST["age"];
$query = " Insert into student(firstname,lastname,age) values ('$firstname', '$lastname', '$age');";
mysqli_query($connect, $query) or die (mysqli_error($connect));
mysqli_close($connect);
}
?>`
但每当我尝试获取数据时,它都不会显示任何内容。
我获取数据的代码如下:
<?php
if($_SERVER["REQUEST_METHOD"]=="POST"){
include 'connection.php';
showStudent();
}
function showStudent()
{
global $connect;
$query = " Select * FROM STUDENT; ";
$result = mysqli_query($connect, $query);
$number_of_rows = mysqli_num_rows($result);
$temp_array = array();
if($number_of_rows > 0) {
while ($row = mysqli_fetch_assoc($result)) {
$temp_array[] = $row;
}
}
header('Content-Type: application/json');
echo json_encode(array("students"=>$temp_array));
mysqli_close($connect);
}
?>
请帮我从表格中取出行。 我的感觉是......它无法将数据存储到数组中!