Question

<output></output>

这是我仍然留下的。

table = soup.findAll('div', attrs={"class":"five columns"})
for data in table:
    para = data.findAll('p')
    print para

Answer 1

您可以尝试使用BeautifulSoup对象.text的{{1}}属性。我进一步用para.text函数拆分了密钥对值，如果你不想拆分，那么只需re.split()

para.text

输出：

from bs4 import BeautifulSoup
import re

a = """<p><span class="four">Location: </span> <span id="wt-loc" title="New Delhi / Safdarjung">New Delhi / Safdarjung</span></p>, <p><span class="four">Current Time: </span> <span id="wtct">Feb 12, 2017 at 10:29:52 am</span></p>, <p><span class="four">Latest Report: </span> Feb 12, 2017 at 8:30 am</p>, <p><span class="four">Visibility: </span> 1 km</p>, <p><span class="four">Pressure: </span> 102.12 kPa</p>, <p><span class="four">Humidity: </span> 95%</p>, <p><span class="four">Dew Point: </span> 10 °C</p>"""

soup = BeautifulSoup(a, 'html.parser')
re.split(r', (?=\s*[A-Z])', soup.text)

Answer 2

使用.text获取p标记下的所有文字，您需要做的是迭代findAll(p)

from bs4 import BeautifulSoup
html = '''<p><span class="four">Location: </span> <span id="wt-loc" title="New Delhi / Safdarjung">New Delhi / Safdarjung</span></p>, <p><span class="four">Current Time: </span> <span id="wtct">Feb 12, 2017 at 10:29:52 am</span></p>, <p><span class="four">Latest Report: </span> Feb 12, 2017 at 8:30 am</p>, <p><span class="four">Visibility: </span> 1 km</p>, <p><span class="four">Pressure: </span> 102.12 kPa</p>, <p><span class="four">Humidity: </span> 95%</p>, <p><span class="four">Dew Point: </span> 10 °C</p>'''

soup = BeautifulSoup(html, 'lxml')

for p in soup.find_all('p'):
    print(p.text)

出：

Location:  New Delhi / Safdarjung
Current Time:  Feb 12, 2017 at 10:29:52 am
Latest Report:  Feb 12, 2017 at 8:30 am
Visibility:  1 km
Pressure:  102.12 kPa
Humidity:  95%
Dew Point:  10 °C

Answer 3

美丽的汤有一个名为get_text()的功能，它允许您获取标签内的所有文本而忽略其他标签。只需致电p.get_text()即可。如果您还想删除空白区域p.get_text(strip=True)。

如何废弃所有p标签内的所有文本，包括span中的文本？

3 个答案: