Question

我使用multipart / mix编写Jersey客户端和服务器来发送请求。每个multipart bodypart都是一个Java类。使用JAXB来编组客户端的对象并在服务器端解组。

编组后，print out是xml文件，但是在发送到服务器后，为什么打印为com.path.data.io.BBody@2b8dd61d？我用whireshark检查，xml被发送过来。

答案：因为该多部分已将其解组为对象。

在服务器端出现此错误 javax.xml.bind.UnmarshalException
- 链接异常： [org.xml.sax.SAXParseException; lineNumber：1; columnNumber：1; prolog中不允许使用内容。]

回答，不需要在这里解组

固定代码如下所示。

Java Class

@XmlRootElement(name="bBody")
@XmlAccessorType(XmlAccessType.FIELD)
public class BBody {

    @XmlAttribute
    String a;
    @XmlElement
    String b;

    public BBody() {}

    public void setA(String a) {
    this.a = a;
}

客户端代码

public ClientResponse multikey(CommonRequest request)
    throws Exception {
String server = request.getURL();
URI path = URI.create(server).resolve("/" + multikey);

Client client = Client.create();
WebResource rRoot = client.resource(path);
WebResource.Builder builder = rRoot.header("Date", date);

// Construct a MultiPart with each operation as a body part
MultiPart multiPart = new MultiPart();
for (BBody bBody : request.getBBodyList()) {
    JAXBContext ctx = JAXBContext.newInstance(BBody.class);
    StringWriter writer = new StringWriter();
    ctx.createMarshaller().marshal(bBody, writer);
    String custString = writer.toString();
    _log.info ("custString is {}", custString);
      // here print  custString is <?xml version="1.0" encoding="UTF-8" standalone="yes"?><bBody a="2c741c38-f120"><b>foo</b></bBody>

    multiPart.bodyPart(new BodyPart(custString,  MediaType.APPLICATION_XML_TYPE));

}
ClientResponse result = builder.type(MultiPartMediaTypes.createMixed()).post(ClientResponse.class, multiPart)
return  new result;

}

服务器端代码

 @POST
 @Path("{ignore: .+}")
 @Consumes("multipart/mixed")
 public Response bulk(MultiPart multiPart,
                 @Context HttpServletRequest request,
                 @Context HttpServletResponse response) throws SuspendExecution {

    for (BodyPart bodyPart : multiPart.getBodyParts()) {
        log.info("bodypart entity dump {}", bodyPart.getEntity());
        //no need extra unmashal
        BBody bBody = bodyPart.getEntityAs(BBody.class)           
    }
}

在多部分Web服务中使用JAXB

0 个答案: