大家好我想将数据和图像路径保存到数据库sql server并将图像保存在asp.net MVC 5的文件夹中。我在互联网上搜索了很多页但没有运气。请任何人都可以告诉我如何创建控制器吗?
我的内容
public class Inquiry
{
[Key]
public int InquiryID { get; set; }
public DateTime InquirDate { get; set; }
public string SignBy { get; set; }
public string Description { get; set; }
public int ParentInqNo { get; set; }
public string Status { get; set; }
public int Number { get; set; }
public string Subject { get; set; }
public string EmpId { get; set; }
public string Attachment { get; set; }
public string InqiurURL { get; set; }
public DateTime EnterDate { get; set; }
}
我的观点
<form action="Create" method="post">
<table>
<tr>
<td>
<input type="date" name="InquirDate" id="InquirDate" placeholder="Date" />
</td>
<td>
<input type="text" id="signby" name="signby" placeholder="signby" />
</td>
<td>
<input type="text" id="description" name="description" placeholder="Description" />
</td>
<td>
<input type="text" id="parentInqNo" name="parentInqNo" placeholder="Parent Inquiry number">
</td>
<td>
<select id="status" name="status">
<option>Draft</option>
<option>Published</option>
</select>
</td>
<td>
<input type="text" id="number" name="number" placeholder="number" />
</td>
</tr>
<tr>
<td>
<input type="text" name="subject" id="subject" placeholder="Subject" />
</td>
<td>
<input type="text" id="empid" name="empid" placeholder="empid" />
</td>
<td>
<input type="file" name="Attachment" id="Attachment" />
</td>
<td>
<input type="text" name="InqiurURL" id="InqiurURL" placeholder="InqiurURL" />
</td>
<td>
<input type="text" name="EnterDate" id="EnterDate" placeholder="EnterDate" />
</td>
</tr>
</table>
<input type="submit" value="Save">
</form>
答案 0 :(得分:1)
尝试在控制器中遵循此代码
public ActionResult Save(FormCollection fc, HttpPostedFileBase Attachment)//Instead of Attachment better to use "file"
{
if (Attachment!= null)
{
Database1Entities db = new Database1Entities();
string ImageName = System.IO.Path.GetFileName(Attachment.FileName);
string physicalPath =Server.MapPath("~/images/"+ ImageName);
// save image in folder
Attachment.SaveAs(physicalPath);
//save new record in database
tblA newRecord = new tblA();
newRecord.empid= fc.empid;
newRecord.subject= fc.subject;
//....Add all field which need to save in db
newRecord.Attachment= ImageName;
db.tblA.Add(newRecord);
db.SaveChanges();
}
return View();
}