Question

我尝试使用jqGrid格式化程序：＆＃34; actions＆＃34;对于远程json url但它会移动行，因为列名和实际返回的数据的数量不匹配（act列在列名中是额外的一个）。我在网上搜索，看起来所有的例子都是本地数据（在页面上），其中json用作键/值，而url：somepage.php返回csv种类的列（没有键，只是值）。我也使用id作为隐藏字段，而所有示例都显示id。我还使用了一个隐藏的列。这是我的colmodel：

url: "manager_json",
                editurl: "manager_edit",
                datatype: "json",
                //data: mydata,
                width:1000,
                //jsonReader: {
                //                repeatitems : false,
                //           },
                colNames: ["","Id","Uid","Custom Id","Image Name","Coord. X","Coord. Y","Gender","Progress","Status","Created","Updated"], 
                colModel: [{"name":"act","template":"actions","formatoptions":{"editformbutton":true}},{"name":"id","align":"center","width":33,"editable":false,"hidden":true},{"name":"uid","align":"center","width":33,"editable":true,"hidden":true,"editrules":{"edithidden":false,"required":false}},{"name":"ta_id","align":"center","width":100,"editrules":{"required":true}},{"name":"image","width":150,"template":"text","editrules":{"required":true}},{"name":"x","width":100,"align":"center","template":"integer","editrules":{"required":true}},{"name":"y","width":100,"align":"center","template":"integer","editrules":{"required":true}},{"name":"gender","width":100,"align":"center","formatter":"select","stype":"select","editrules":{"required":true},"edittype":"select","editoptions":{"value":"f:Female;m:Male","defaultValue":"m"},"searchoptions":{"sopt":["eq","ne"],"value":":Any;f:Female;m:Male"}},{"name":"progress","width":120,"align":"center","formatter":"select","stype":"select","editrules":{"required":true},"editable":false,"edittype":"select","editoptions":{"value":"-:New;pf:Process Failed;ps:Process Scheduled;pss:Process Success;p:Processing...;s:Staging;tf:Test Failed;ts:Test Scheduled;tss:Test Success;t:Testing...","defaultValue":"m"},"searchoptions":{"sopt":["eq","ne"],"value":":Any;-:New;pf:Process Failed;ps:Process Scheduled;pss:Process Success;p:Processing...;s:Staging;tf:Test Failed;ts:Test Scheduled;tss:Test Success;t:Testing..."}},{"name":"status","width":100,"align":"center","formatter":"select","stype":"select","edittype":"select","editoptions":{"value":"a:Active;n:New","defaultValue":"m"},"searchoptions":{"sopt":["eq","ne"],"value":":Any;a:Active;n:New"}},{"name":"date_created","width":150,"template":"text","editable":false},{"name":"last_updated","width":150,"template":"text","editable":false}]

根据jqgrid规范，这是我服务器（db）的实际数据：

{"page":1,"total":1,"records":7,"rows":[{"id":32,"cell":[32,"889daf31ff3e49544f52850258439600","2uu","2ok",2,2,"m","-","a","2017-02-10 18:57:05","2017-02-10 23:37:12"]},{"id":30,"cell":[30,"","11","11",1,1,"m","-","a","2017-02-10 18:01:52","2017-02-10 18:01:52"]},{"id":29,"cell":[29,"aaa","ww222111uu","11",1,1,"m","-","a","2017-02-10 18:00:36","2017-02-10 23:37:08"]},{"id":27,"cell":[27,"","11","1",1,1,"m","-","a","2017-02-10 17:57:41","2017-02-10 17:57:41"]},{"id":25,"cell":[25,"","4tt","4img",4,4,"f","-","n","2017-02-10 17:50:21","2017-02-11 00:26:03"]},{"id":24,"cell":[24,"","1","1",1,1,"m","-","a","2017-02-10 17:49:38","2017-02-10 17:49:38"]},{"id":22,"cell":[22,"","bbb","imam 222",2,22,"f","p","n","2017-02-08 20:14:55","2017-02-10 13:27:57"]}]}

正如您所见，单元格行的列数少于colNames和colModel。此外，还会隐藏ID和uid列。我在db中添加了额外的假列，但它没有帮助

我正在使用jqGrid 4.13.7-pre

Answer 1

我建议你返回像

这样的对象

{
    "id": 32,
    "uid": "889daf31ff3e49544f52850258439600",
    "ta_id": "2uu",
    "image": "2ok",
    "x": 2,
    "y": 2,
    "gender": "m",
    "progress": "-",
    "status": "a",
    "date_created": "2017-02-10 18:57:05",
    "last_updated": "2017-02-10 23:37:12"
}

而不是

{
    "id": 32,
    "cell": [
        32, "889daf31ff3e49544f52850258439600", "2uu", "2ok", 2, 2, "m", "-", "a",
        "2017-02-10 18:57:05", "2017-02-10 23:37:12"
    ]
}

作为服务器响应。它将简化您的代码。

如果您确实需要处理数据的当前格式，则必须使用选项

强制repeatitems: false模式

jsonReader: {
    repeatitems: false
}

并使用jsonmap的{{1}}属性来通知jqGrid项目的哪个元素应该读取列数据。 colModel可以是字符串形式，如

jsonmap

或以函数形式：

jsonmap: "cell.1"

为了使代码更易于维护，您可以定义像

这样的对象

jsonmap: function (item) {
    return item.cell[1];
}

通过列名提供var columnOrder = { id: 0, uid: 1, ta_id: 2, image: 3, x: 4, y: 5, gender: 6, progress: 7, status: 8, date_created: 9, last_updated: 10 };数组中的索引并使用cell之类的

jsonmap

演示https://jsfiddle.net/OlegKi/ozzgnaeh/2/演示了这种方法。

jqGrid：formatter：＆＃34; actions＆＃34;不适用于远程json url

1 个答案: