c＃如何在下次启动时维护创建的动态按钮

Question

我几天都遇到了麻烦。我在运行时创建了一个动态按钮，但它会在下次启动时消失。请帮忙。下面是我的编码。

private void button1_Click(object sender, EventArgs e)
    {
        createNewTable createTable = new createNewTable();

        DialogResult dResult = createTable.ShowDialog();
        string table_name = "";

        if (dResult == DialogResult.OK)
        {
            table_name = createTable.tableName;
            createTable.Dispose();
        }
        else if (dResult == DialogResult.Cancel)
        {
            createTable.Dispose();
        }

        if(table_name != string.Empty){
            Button textbox = new Button();

            textbox.Name = "btn_" + table_name;
            textbox.Text = table_name;
            textbox.Height = 55;
            textbox.Width = 123;
            textbox.MouseDown += new MouseEventHandler(textbox_MouseDown);
            textbox.MouseMove += new MouseEventHandler(textbox_MouseMove);
            textbox.MouseUp += new MouseEventHandler(textbox_MouseUp);
            textbox.ContextMenuStrip = contextMenuStrip1;

            this.Controls.Add(textbox);
            }

}

我搜索了一些信息，比如使用XMLSerialize / application设置但它没有为我提供任何示例如何使用XMLSerialize添加动态按钮。请帮忙..