Question

这里有三个表格tbl_users，tbl_account_details，tbl_attendance。table tbl_users看起来像这样

user_id     username            role_id     activated   banned  
    1        admin                  1           1         0         
    36       siraj                  3           1         0     
    37       faizal                 3           1         0     
    38       nesru                  3           1         0     
    40       jaseer                 3           1         0     
    42       maltu                  3           1         0     
    43       shahul                 3           1         0

表tbl_account_details看起来像这样

account_details_id  user_id     fullname        designations_id     
    1                 1       Administrator         1   
    33                36        siraj               2   
    34                37        faizal              3   
    35                38        nesru               3   
    37                40        jaseer              4   
    39                42        maltu               4   
    40                43        shahul              2

我的tbl_attendance表看起来像这样

attendance_id   user_id      date_in        attendance_status status 0=absent 1=present 3 = onleave 4 = onoff
    1            1          2017-02-05      1
    2            36         2017-02-11      4
    3            36         2017-02-11      4
    4            36         2017-02-11      3
    5            1          2017-02-02      1
    6            36         2017-02-01      1

我希望在users当天users onleave和onoff之内的所有tbl_attendance得到3。是public function get_manager_cordinator_users($date) { $this->db->select('tbl_account_details.*', FALSE); $this->db->select('tbl_users.*'); $this->db->join('tbl_account_details', 'tbl_users.user_id = tbl_account_details.user_id', 'left'); $this->db->where(array('designations_id' => 2)); $this->db->or_where(array('designations_id' => 3)); $this->db->where('tbl_users.user_id NOT IN(SELECT user_id FROM tbl_attendance WHERE tbl_attendance.date_in='.$date.' && attendance_status=3 OR attendance_status=4 )'); $query_result = $this->db->get('tbl_users'); $result = $query_result->result(); return $result; } my controller looks like this $date=date('Y-m-d'); $data['assign_user'] = $this->Project_model->get_manager_cordinator_users($date);，关闭是4。为了让我写了一个看起来像这样的查询

{{1}}

请帮我解决......

Answer 1

我已经创建了一个查询，它将返回具有designation_id 2和3的用户数据，也没有出勤率_status 3和4

您的控制器代码很好 -

$date = date('Y-m-d');
$data['assign_user'] = $this->Project_model->get_manager_cordinator_users($date);

只需更改下面的模型代码 -

public function get_manager_cordinator_users($date)
{
    $this->db->select( 'tbl_users.user_id, tbl_users.username,                                             tbl_account_details.designations_id, tbl_attendance.date_in, tbl_attendance.attendance_status' );
    $this->db->from( 'tbl_users' );
    $this->db->join( 'tbl_account_details', 'tbl_account_details.user_id = tbl_users.user_id' );
    $this->db->join( 'tbl_attendance', 'tbl_attendance.user_id = tbl_users.user_id' );
    $this->db->where( 'tbl_attendance.date_in', $date );
    $this->db->where('tbl_users.banned', 0);
    $this->db->where('tbl_users.activated', 1);
    $this->db->where_in( 'tbl_account_details.designations_id', array( '2', '3' ) );
    $this->db->where_not_in( 'tbl_attendance.attendance_status', array( '3', '4' ) );
    return $this->db->get()->result();
}

它将为您提供所需的用户数据。

Answer 2

$ this-＆gt; db-＆gt; select（'*） - ＆gt; from（'tbl_users'） - ＆gt; where（'tbl_attendance.attendance_status＆lt; = 2'） - ＆gt; where（'tbl_attendance.data_in ='，date（'Ym-d'）） - ＆gt; join（'tbl_attendance'，'tbl_attendance.user_id ='tbl_users.user_id'，'left'） - ＆gt; get（） - ＆gt; result（）; < / p>

Answer 3

现在我明白了

public function get_manager_cordinator_users()
{
 $date=date('Y-m-d');
 $this->db->select('tbl_users.*');
 $this->db->join('tbl_account_details', 'tbl_users.user_id = tbl_account_details.user_id', 'left');
 $this->db->where('tbl_users.user_id NOT IN(SELECT user_id FROM tbl_attendance WHERE tbl_attendance.date_in= "'.$date.'" AND tbl_attendance.attendance_status IN (3,4) ) ');

 $this->db->where_in( 'tbl_account_details.designations_id', array( '2','3' ) );
 $this->db->where('tbl_users.banned', 0);
 $this->db->where('tbl_users.activated', 1);

 $query_result = $this->db->get('tbl_users');
 $result = $query_result->result();
 return $result;



}

Answer 4

使用此

http://localhost/moviesearch/action/movies.html

codeigniter中的多个连接

4 个答案: