Question

我正在尝试运行该应用，但它显示2个错误。红线位于Label1.Txt和Label2.Txt下。请参阅以下代码

        public object Label1 { get; private set; }
        public object Label2 { get; private set; }

        protected void Page_Load(object sender, EventArgs e)
        {
            var username = HttpContext.Current.Session["username"];

            if (username == null)
            {
                Response.Redirect("login.aspx");
            }    
        }

        protected void submitt_Click(object sender, EventArgs e)
        {
            try
            {   con.Open();
                SqlCommand command = new SqlCommand("insert into [Students] values ('" + ID.Text + "','" + FN.Text + "', '" + LN.Text + "', '" + Country1.Text + "', '" + gender.SelectedValue + "',  '" + email.Text + "', '" + passportNo.Text + "', '" + PlaceOfIssue.Text + "', '" + issue.Text + "',  '" + Expiry.Text + "', '" + VisaNo.Text + "', '" + VisaExpiry.Text + "', '" + EmiratesNo.Text + "', '" + EmiaratesExpiry.Text + "');", con);
                command.ExecuteNonQuery();
                con.Close();
                Label1.Text = "Uploaded Successfully"; 
            }
            catch (Exception ex)
            {
                Label2.Text = "Same data cannot be submitted again"; 
            }    
        }
    }
}

Answer 1

label1和label2被声明为object类型。 Text没有属性object，因此会出现此错误。你可能需要施放它们。

Answer 2

你需要改变这个

  public object Label1 { get; private set; }
  public object Label2 { get; private set; }

到此：

  public string Label1 { get; private set; }
  public string Label2 { get; private set; }

但这只会修复异常并且不会显示消息..

如果要在标签中显示消息，则需要在HTML中声明标签，如：

  <asp:label id="Label1" runat="server" />
  <asp:label id="Label2" runat="server" />

然后将代码更改为：

    protected void submitt_Click(object sender, EventArgs e)
    {
        try
        {   con.Open();
            SqlCommand command = new SqlCommand("insert into [Students] values ('" + ID.Text + "','" + FN.Text + "', '" + LN.Text + "', '" + Country1.Text + "', '" + gender.SelectedValue + "',  '" + email.Text + "', '" + passportNo.Text + "', '" + PlaceOfIssue.Text + "', '" + issue.Text + "',  '" + Expiry.Text + "', '" + VisaNo.Text + "', '" + VisaExpiry.Text + "', '" + EmiratesNo.Text + "', '" + EmiaratesExpiry.Text + "');", con);
            command.ExecuteNonQuery();
            con.Close();
            Label1.Text = "Uploaded Successfully"; 
        }
        catch (Exception ex)
        {
            Label2.Text = "Same data cannot be submitted again"; 
        }    
    }
}

并从代码中删除以下内容

public string Label1 { get; private set; }
public string Label2 { get; private set; }

在执行当前Web请求asp net期间生成了未处理的异常

2 个答案: