Question

我已经创建了一个sql查询，并希望以随机顺序显示数据，就像每次刷新它应该调出随机数据一样

这是我的代码

<?php 
if(isset($_POST['new_list'])) {
    $class_id = $_POST['get_class_id'];
    $user_id  = $_POST['user_id'];

    $sql2 = mysqli_query($connection, "SELECT * FROM get_help WHERE class = '$class_id' AND status = 'Pending' AND user_id != '$user_id' ORDER BY id ASC LIMIT 1");
    while($record = mysqli_fetch_assoc($sql2)) {
        $sql3  = mysqli_query($connection, "SELECT * FROM users WHERE uid = '".$record['user_id']."' AND btc_email != ''");
        if(mysqli_num_rows($sql3)) {
        $data2 = mysqli_fetch_array($sql3); 
?>
        <tr class="odd">
            <td><?php echo $data2["first_name"] . " " . $data2["last_name"]; ?></td>
            <td><?php echo $data2["email"]; ?></td>
            <td><?php echo $data2["phone"]; ?></td>
            <td>
            <p>
            Click donate to see receipient bitcoin address. Input Hash ID after transfer    
            </p>
            </td>
            <td>
            <div class="col-md-2"></div>
            <div class="col-md-2">
                <button type="button" onclick="get_details(<?php echo $record['id']; ?>);" name="donate" class="btn btn-red">Donate</button>
            </div>
            </td>
        </tr>
    <?php } ?>  
<?php } ?>
<?php } ?>

Answer 1

您可以使用ORDER BY RAND（）来代替在第一个查询中使用ORDER BY ID。这将为您的显示生成随机结果：

$sql2 = mysqli_query($connection, "SELECT * FROM get_help WHERE class = '$class_id' AND status = 'Pending' AND user_id != '$user_id' ORDER BY RAND() LIMIT 1");

请记住在$ _POST数据周围使用htmlentities（）以确保它对数据库查询是安全的，例如：

$class_id = htmlentities($_POST['get_class_id']);
$user_id  = htmlentities($_POST['user_id']);

以随机顺序获取数据

1 个答案: