我有两张桌子。一个是基本的客户信息,一个是订购信息。
我正在尝试找到订单状态为'placement'or'cancelled'的最大订单日期(订单日期)。如果放置或取消状态,我不在乎。我只想要最近的订单。
第一个表(信息)
CustomerID LAST NAME FIRST NAME
1 AB BOB
2 BC ROBERT
3 AA JOHN
第二张表(订单)
CustomerID Order Date Order Status
1 12/16/2016 placed
2 8/5/2016 cancelled
1 5/8/2015 cancelled
2 8/9/2016 placed
3 7/15/2016 cancelled
3 8/20/2015 placed
我希望结果是:
CustomerID FirstName LastName OrderDate OrderStatus
1 AB BOB 12/16/2016 placed
2 BA ROBERT 8/9/2016 placed
3 AA JOHN 7/15/2016 cancelled
这是我的SQL语法
SELECT distinct Info.CustomerID, Info.Lastname,Info.Firstname
FROM INFO
INNER JOIN
(SELECT
order.CustomerID, LastOrderDate=max(OrderDate),order.OrderStatus
FROM Order
GROUP BY order.CustomerID, order.orderstatus)a
ON a.CustomerID=Info.CustomerID
这不起作用,因为它按订单状态分组,它给出了每个所有订单状态的最大日期。然后我试了
SELECT distinct Info.CustomerID, Info.Lastname,Info.Firstname, Order.OrderStatus
FROM INFO, Order
INNER JOIN
(SELECT
order.CustomerID, LastOrderDate=max(OrderDate)
FROM Order
GROUP BY order.CustomerID)a
ON a.CustomerID=Info.CustomerID
这不起作用,因为它说无法绑定Info.CustomerID。
有什么帮助吗?谢谢!
答案 0 :(得分:0)
您可以尝试以下查询:
SELECT c.customerid, c.last_name, c.first_name, o.order_status, MAX(order_date)
FROM customer c JOIN order ON c.customerid = o.customerid
WHERE o.order_status IN ('placed', 'cancelled')
GROUP BY c.customerid, c.last_name, c.first_name, o.order_status;
<强>更新强>
如果您不希望订单状态为max
日期,则可以将其从group by
中删除,例如:
SELECT c.customerid, c.last_name, c.first_name, MAX(order_date)
FROM customer c JOIN order ON c.customerid = o.customerid
WHERE o.order_status IN ('placed', 'cancelled')
GROUP BY c.customerid, c.last_name, c.first_name;
另一次更新
如果在同一天下订单并取消订单,以下查询将返回两条记录:
SELECT c.customerid, c.first_name, c.last_name, o.order_date, o.order_status
FROM customer c JOIN
(SELECT o1.customerid, o1.order_date, o1.order_status
FROM `order` o1 JOIN
(SELECT o.customerid, max(o.order_date) as max_date
FROM `order` o
WHERE o.order_status in ('placed', 'cancelled')
GROUP BY o.customerid) o2
ON o1.customerid = o2.customerid and o1.order_date = o2.max_date) o
ON c.customerid = o.customerid;
这里是 SQL Fiddle 。