绕过MouseDown事件或可能删除方法

Question

我有一个显示Sierpinski Triangle的java程序。每次单击小程序中的三角形时，它都会为每个三角形添加一个三角形。有没有办法可以绕过mouseDown方法，只需硬编码三角形就可以显示我想要的任何迭代次数。让我们说我希望三角形显示图像，好像我点击了5次。我该怎么做？

public class SierpinskiTriangle extends Applet {

//private static final long serialVersionUID = 1L;
Graphics g;

int deep = 0;

public void paint() {
    setBackground(new Color(255,255,255));
}

public boolean mouseDown(Event ev, int x, int y) {
    if (!ev.metaDown()) deep += 1;
    else if (deep>0) deep -= 1;
    repaint();
    return true;
}


public void paint(Graphics g) {
    // Create triangle
    int px[] = {20, 400, 210};
    int py[] = {400, 400, 20};

    g.setColor(Color.black);
    g.fillPolygon(px, py, 3);

    for(int i = 0; i < 5; i++)
    {
        paintTriangle(g, new Point(20,400),new Point(400,400),new Point(210,20), deep);
        i++;
    }
}

public void paintTriangle(Graphics g, Point a, Point b, Point c, int lvl) {

    Point a1,b1,c1, a2,b2,c2, a3,b3,c3;

    if (lvl==0) return;

    lvl = 3;

    // In the given triangle, amended to include an upside-down triangle
    int px[] = {c.x, (c.x+b.x)/2, (a.x+c.x)/2};
    int py[] = {b.y, (c.y+a.y)/2, (c.y+a.y)/2};

    g.setColor(Color.white);
    g.fillPolygon(px, py, 3);
    g.setColor(Color.red);
    g.drawPolygon(px, py, 3);

    // 3 new triangles 
    a1 = a;
    b1 = new Point(c.x, b.y);
    c1 = new Point((a.x+c.x)/2, (c.y+a.y)/2);
    paintTriangle(g, a1, b1, c1, lvl);

    a2 = new Point(c.x, b.y);
    b2 = b;
    c2 = new Point((c.x+b.x)/2, (c.y+a.y)/2);
    paintTriangle(g, a2, b2, c2, lvl);

    a3 = new Point((a.x+c.x)/2, (c.y+a.y)/2);
    b3 = new Point((c.x+b.x)/2, (c.y+a.y)/2);
    c3 = c;
    paintTriangle(g, a3, b3, c3, lvl);
  }
}