我正在尝试运行一个查询,该查询将显示该经理的经理ID和最低薪员工。它还将排除最低工资为6000美元或更低的任何团体,并且不知道经理。我的代码显示所有这些,除了收入最低的员工。这是我的代码。
select departments.manager_id, employees.salary
from hr.employees, hr.departments, hr.jobs
where employees.department_id = departments.department_id
AND jobs.job_id = employees.job_id
AND departments.manager_id IS NOT NULL
AND salary NOT IN
(select salary
from hr.employees
where salary <= 6000)
答案 0 :(得分:0)
以下是基于EMP表格可能有帮助的内容......
select * from (
select min(e1.sal) over( partition by m1.ename ) minsal
, e1.mgr
, e1.ename
, m1.ename Manager
, e1.sal sal
from emp e1
join emp m1
on e1.mgr = m1.empno
)
where minsal > 1500
MINSAL MGR ENAME MANAGER SAL
---------- ---------- ---------- ---------- ----------
3000 7566 FORD JONES 3000
3000 7566 SCOTT JONES 3000
2450 7839 CLARK KING 2450
2450 7839 BLAKE KING 2850
2450 7839 JONES KING 2975