Question

我得到了我的c ++课程中典型距离的作业。然而，在这个问题上，老师说我不能使用＆＃34; for＆＃34;循环，我只允许使用＆＃34; while循环＆＃34;，所以我坚持使用此代码。

问题是小时应该显示单独行驶的距离，但它显示每小时行驶距离的总量。

#include <iostream>
using namespace std;

int main()
{
    double distance,
           speed,
           time,
           counter=1;


    cout << "This program will display the total distance travel each hour.\n\n";

    cout << " What is the speed of the vehicle in mph?  ";
    cin >> speed;

    while(speed < 0)
    {
        cout << " Please enter a positive number for the speed:  ";
        cin >> speed;
    }

    cout << " How many hours has it traveled?   ";
    cin >> time;

    while(time < 1)
    {
        cout << " Please enter a number greater than 1 for the hours:  ";
        cin >> time;
    }


    cout << endl;
    cout << " Hour" << "\t\t" << " Distance Traveled" << endl;
    cout << " ------------------------------------" << endl;

    while(counter <= time)
    {
        distance = speed * time;
        cout << counter << "\t\t" << distance << endl;
        counter++;

    }

    return 0;
}

Answer 1

假设你想分别计算每个小时的行走距离（从我能从代码中理解）;这是因为每次在counter <= time的while循环中迭代时，都会计算该时间量的距离。假设时间= 1小时，您的代码计算1小时内行进的距离并显示它。当时间为2小时时，它分别计算1小时和2小时（总距离不是2小时）的行进距离。

例如：

time = 2, speed = 60 kmph

将打印

1 60
2 120

其中120是2小时内的总距离，而不是从1小时到第2小时的距离。

如果您需要计算每小时行驶的距离，您的时间应该是恒定的，并且是1小时（假设速度在整个时间内保持不变）。要在while循环中使用它，请使用：

distance = (speed * counter) - (speed *(counter - 1))

在第n小时行进的距离是n小时内的总距离减去（n-1）小时内的行进距离。

Answer 2

如果它真的像距离=速度*时间一样简单，请尝试。您似乎将变量print(df) X Y 0 1.0 8 1 2.0 3 2 8.0 2 3 6.0 7 4 1.0 2 5 3.0 2和counter混为一谈。只需在每个增量使用time，即counter的本地值。

time

测试

#include <iostream>
using namespace std;

int main()
{
    double distance,
            speed,
            time,
            counter=1;


    cout << "This program will display the total distance travel each hour.\n\n";

    cout << " What is the speed of the vehicle in mph?  ";
    cin >> speed;

    while(speed < 0)
    {
        cout << " Please enter a positive number for the speed:  ";
        cin >> speed;
    }

    cout << " How many hours has it traveled?   ";
    cin >> time;

    while(time < 1)
    {
        cout << " Please enter a number greater than 1 for the hours:  ";
        cin >> time;
    }


    cout << endl;
    cout << " Hour" << "\t\t" << " Distance Traveled" << endl;
    cout << " ------------------------------------" << endl;

    while(counter <= time)
    {
        distance = speed * counter;
        cout << counter << "\t\t" << distance << endl;
        counter++;

    }

    return 0;
}

如何修复这个C ++程序？

2 个答案: