Question

我有一个ViewPager，在它下面有一个Retrofit中有四个标签，我目前正在做的是在文本更改时使用RxTextView.textChangeEvents(searchbar.getEditText()) .debounce(400, TimeUnit.MILLISECONDS) .filter(new Func1<TextViewTextChangeEvent, Boolean>() { @Override public Boolean call(TextViewTextChangeEvent text) { return (text.text().length() > 2); } }) .subscribeOn(AndroidSchedulers.mainThread()) .observeOn(Schedulers.io()) .switchMap(new Func1<TextViewTextChangeEvent, Observable<?>>() { @Override public Observable<?> call(TextViewTextChangeEvent textViewTextChangeEvent) { String searchBarText = textViewTextChangeEvent.text().toString(); switch (visibleTab) { case TAGS: return presenter.executeSearchPostsByTag(searchBarText, String.valueOf(0)); case PEOPLE: return presenter.executeSearchPostsByPeople(searchBarText, String.valueOf(0)); case COMPANIES: return presenter.executeSearchPostsByCompanies(searchBarText, String.valueOf(0)); case JOBS: return presenter.executeSearchPostsByJobs(searchBarText, String.valueOf(0)); default: return presenter.executeSearchPostsByTag(searchBarText, String.valueOf(0)) .toCompletable().toObservable(); } } }) .subscribeOn(Schedulers.io()) .observeOn(AndroidSchedulers.mainThread()) .subscribe(new Observer<Object>() { // here I use EventBus to pass the results to the Fragments (Tabs) // ... code omitted ...向Rest服务执行请求

EditText

从每个标签的代码中可以看出，我有不同的请求。

但现在需求已经发生变化，对于combineLatest' so I added all four calls to中的每个文本更改，我必须同时执行所有四个请求。

我搜索了很多，我发现的是我可以使用Observable.combineLatest(presenter.executeSearchPostsByTag( /** what to add as queryText **/ ), presenter.executeSearchPostsByJobs(/** what to add here as queryText**/), //omits the other two calls) combineLatest`，但由于它们都依赖于文本更改，所以没有发生任何事情。

queryText

如上所示，我不知道如何通过combineLatest。必须有一种方法将RxTextView.textChangeEvents(searchbar.getEditText())...代码与switchMap代码相结合，直到我在开头发布的combineLatest但我找不到它。

编辑：也许.map(new Func1<String, Boolean>() { @Override public Boolean call(String s) { presenter.executeSearchPostsByTag(s, String.valueOf(0)); presenter.executeSearchPostsByPeople(s, String.valueOf(0)); presenter.executeSearchPostsByJobs(s, String.valueOf(0)); presenter.executeSearchPostsByCompanies(s, String.valueOf(0)); return true; } })错了，我可以做类似的事情：

OPENROWSET

但后来我不知道如何将结果发送给订阅者

Answer 1

你很亲密。只需将开关地图替换为：

即可

.flatMap(new Func1<TextViewTextChangeEvent, Observable<CombinedData>>() {
    @Override
    public Observable<CombinedData> call(TextViewTextChangeEvent textViewTextChangeEvent) {
        String searchBarText = textViewTextChangeEvent.text().toString();

        return Observable.combineLatest(
                presenter.executeSearchPostsByTag(searchBarText, String.valueOf(0)), 
                presenter.executeSearchPostsByPeople(searchBarText, String.valueOf(0)),
                ...);
        }    
})

为了更好的可读性，请创建一个提取组合部分的方法。类似的东西：

Observable<CombinedData> fetchData(String searchBarText) {
    return Observable.combineLatest(
            presenter.executeSearchPostsByTag(searchBarText, String.valueOf(0)),
            presenter.executeSearchPostsByPeople(searchBarText, String.valueOf(0)),
            ...);
}

但如果可以的话，最好将它分成四部分。声明一个Observable：

Observable<TextViewTextChangeEvent> requestObservable = RxTextView.textChangeEvents(searchbar.getEditText())
        .debounce(400, TimeUnit.MILLISECONDS)
        .filter(new Func1<TextViewTextChangeEvent, Boolean>() {
            @Override
            public Boolean call(TextViewTextChangeEvent text) {
                return (text.text().length() > 2);
            }
        })
        .subscribeOn(AndroidSchedulers.mainThread())
        .observeOn(Schedulers.io());

然后，您为每个请求订阅四次：

.flatMap(new Func1<TextViewTextChangeEvent, Observable<Post>>() {
    @Override
    public Observable<Post> call(TextViewTextChangeEvent textViewTextChangeEvent) {
        String searchBarText = textViewTextChangeEvent.text().toString();
        return presenter.executeSearchPostsByTag(searchBarText, String.valueOf(0));
        }
})
.subscribe(...

执行依赖于单个RxTextView的多个不同的改装调用

1 个答案: