我正在创建一个应该自动停止<b>
的程序。所以请告诉我如何,这是我想的一点点:
var time = date.getTime();
var seconds = 0;
if (time + seconds == date.getTime())
{
// Stop everything i do by myself :)
}
答案 0 :(得分:3)
这样的事情:
<!-- component template -->
<script type="text/x-template" id="grid-template">
<table>
<thead>
<tr>
<th v-for="key in columns"
@click="sortBy(key)"
:class="{ active: sortKey == key }">
{{ key | capitalize }}
<span class="arrow" :class="sortOrders[key] > 0 ? 'asc' : 'dsc'">
</span>
</th>
</tr>
</thead>
<tbody>
<tr v-for="entry in filteredData">
<td v-for="key in columns">
{{entry[key]}}
</td>
</tr>
</tbody>
</table>
</script>
<!-- demo root element -->
<div id="demo">
<form id="search">
Search <input name="query" v-model="searchQuery">
</form>
<demo-grid
:data="gridData"
:columns="gridColumns"
:filter-key="searchQuery">
</demo-grid>
</div>
// register the grid component
Vue.component('demo-grid', {
template: '#grid-template',
props: {
data: Array,
columns: Array,
filterKey: String
},
data: function () {
var sortOrders = {}
this.columns.forEach(function (key) {
sortOrders[key] = 1
})
return {
sortKey: '',
sortOrders: sortOrders
}
},
computed: {
filteredData: function () {
var sortKey = this.sortKey
var filterKey = this.filterKey && this.filterKey.toLowerCase()
var order = this.sortOrders[sortKey] || 1
var data = this.data
if (filterKey) {
data = data.filter(function (row) {
return Object.keys(row).some(function (key) {
return String(row[key]).toLowerCase().indexOf(filterKey) > -1
})
})
}
if (sortKey) {
data = data.slice().sort(function (a, b) {
a = a[sortKey]
b = b[sortKey]
return (a === b ? 0 : a > b ? 1 : -1) * order
})
}
return data
}
},
filters: {
capitalize: function (str) {
return str.charAt(0).toUpperCase() + str.slice(1)
}
},
methods: {
sortBy: function (key) {
this.sortKey = key
this.sortOrders[key] = this.sortOrders[key] * -1
}
}
})
// bootstrap the demo
var demo = new Vue({
el: '#demo',
data: {
searchQuery: '',
gridColumns: ['name', 'power'],
gridData: [
{ name: 'Chuck Norris', power: Infinity },
{ name: 'Bruce Lee', power: 9000 },
{ name: 'Jackie Chan', power: 7000 },
{ name: 'Jet Li', power: 8000 },
{ name: 'Jet Li', power: 8000 },
{ name: 'Jet Li', power: 8000 },
{ name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 }, { name: 'Jet Li', power: 8000 },
]
}
})
答案 1 :(得分:0)
我们可以结合使用 setInterval
和 setTimeout
来实现这一点。
function doStuff(){
//do whatever you need to do
}
var is_running = true;
setTimeout(function(){
is_running = false; //Stop the program
}, 1000 * 60 * 60); //Do this after 1 hour
while(is_running){
doStuff(); //whatever your function does
}