如何计算表中的多个列并使用php显示它们

Question

我有一张包含一些列的表格（见下图）：

我的表：

我想计算那些列中的值（多少＆＃34; ok＆＃34;＆＃34; no＆＃34;我有超过05，超过15等列）使用一些过滤器（即在1.20和1.50之间的best_bets）并使用php

显示它们

现在我可以使用以下代码对列进行计数：

    $result=mysql_query("SELECT count(over15) as total from risultati WHERE over15 = 'OK' AND best_bets >= 1.15 AND best_bets <= 1.50");
$data=mysql_fetch_assoc($result);
echo $data['total'];

但我想为更多列做这件事

此致

编辑：我试过这种方式，但它不起作用：

$result=mysql_query("SELECT SUM(CASE WHEN over05 = 'OK' THEN 1 ELSE 0 END) AS OK_05,
       SUM(CASE WHEN over15 = 'OK' THEN 1 ELSE 0 END) AS OK_15,
       SUM(CASE WHEN over25 = 'OK' THEN 1 ELSE 0 END) AS OK_25,
       SUM(CASE WHEN over35 = 'OK' THEN 1 ELSE 0 END) AS OK_35,
       SUM(CASE WHEN over45 = 'OK' THEN 1 ELSE 0 END) AS OK_45
FROM risultati
WHERE best_bets BETWEEN 1.15 AND 1.5O");
$data=mysql_fetch_assoc($result);
echo $data['OK_15'];
echo $data['OK_25'];
echo $data['OK_35'];
echo $data['OK_45'];

edit2：我也尝试过另一种方式，但没有：

$result=mysql_query("SELECT SUM(CASE WHEN over05 = 'OK' THEN 1 ELSE 0 END) AS OK_05,
       SUM(CASE WHEN over15 = 'OK' THEN 1 ELSE 0 END) AS OK_15,
       SUM(CASE WHEN over25 = 'OK' THEN 1 ELSE 0 END) AS OK_25,
       SUM(CASE WHEN over35 = 'OK' THEN 1 ELSE 0 END) AS OK_35,
       SUM(CASE WHEN over45 = 'OK' THEN 1 ELSE 0 END) AS OK_45
FROM risultati
WHERE best_bets BETWEEN 1.15 AND 1.5O");



while ($row = mysql_fetch_assoc($result)) 
{
    echo $row['OK_05'];
    echo $row['OK_15'];
    echo $row['OK_25'];
    echo $row['OK_35'];
    echo $row['OK_45'];

}

Answer 1

使用条件聚合：

SELECT SUM(CASE WHEN over05 = 'OK' THEN 1 ELSE 0 END) AS OK_05,
       SUM(CASE WHEN over15 = 'OK' THEN 1 ELSE 0 END) AS OK_15,
       SUM(CASE WHEN over25 = 'OK' THEN 1 ELSE 0 END) AS OK_25,
       SUM(CASE WHEN over35 = 'OK' THEN 1 ELSE 0 END) AS OK_35,
       SUM(CASE WHEN over45 = 'OK' THEN 1 ELSE 0 END) AS OK_45
FROM risultati
WHERE best_bets BETWEEN 1.15 AND 1.5O    -- or whatever restrictions you want

此方法允许您在单个查询中收集所有年龄列的统计信息，而将列检查为“确定”。限制一个查询中的单个列。