我正在尝试将这个简单的C片段翻译成MIPS:
int leaf_example(int g, int h, int i, int j) {
int f;
f = (g + h) - (i + j);
return f;
}
这是我的MIPS代码:
.text
main:
leaf:
addi $sp, $sp, -8 #adjust stack to make room for 3 items
sw $t1, 8($sp) #save register $t1 for use in memory location 8
sw $t0, 4($sp) #save register $t0 for use in memory location 4
sw $s0, 0($sp) #save register $s0 for use in memory location 0
add $t0, $a0, $a1 #register $t0 contains $a0 + $a1
add $t1, $a2, $a3 #register $t1 contains $a2 + $a3
sub $s0, $t0, $t1 #$t0 = $t0 - $t1 -> $t0 = ($a0 + $a1) - ($a2 + $a3)
add $v0, $s0, $zero #copy $s0 to return register $v0
#Before returning, we restore three original values of registers we pushed onto stack by popping them
lw $s0, 0($sp) #restore register $s0 for caller
lw $t0, 4($sp) #restore register $t0 for caller
lw $t1, 8($sp) #restore register $t1 for caller
addi $sp, $sp, 8 #adjust stack to delete 3 items
jr $ra #jump back to calling routine
然而,当我编译并尝试运行它时,它给了我这个错误:
“错误:程序计数器值无效:0x00000000
Go:执行因错误而终止。“
我根本不明白这个错误。有人能指出我正确的方向吗?
答案 0 :(得分:1)
似乎MARS将注册$ra
初始化为0x00000000
并使用jr $ra
,该程序跳转到0x00000000
,这被视为无效。
我想你应该在leaf
之后编写一些调用函数main:
(然后通过system call no.10退出)的代码来测试你的函数。
答案 1 :(得分:0)
实际上你不需要保存和恢复$t0,$t1
因为如果调用函数不使用那些寄存器,
保存和恢复它们的努力被浪费了。为了避免这种浪费,MIPS进行了划分
注册到保留和非保留的类别。保留的寄存器包括$s0 – $s7
(因此保存了它们的名称)。非保留寄存器
包括$t0 – $t9
(因此他们的名字,临时)。一个函数必须保存和
恢复它希望使用的任何保留寄存器,但它可以更改
非保留的寄存器是自由的。
.text
main:
addi $a0,$0,1 #argument 0 = 1
addi $a1,$0,2 #argument 1 = 2
addi $a2,$0,3 #argument 2 = 3
addi $a3,$0,4 #argument 3 = 4
jal leaf # call function leaf
add $s0,$v0,$zero # return value
li $v0,10
syscall
leaf:
addi $sp, $sp, -12 #adjust stack to make room for 3 items
sw $s0, 8($sp) #save register $t1 for use in memory location 8
sw $t0, 4($sp) #save register $t0 for use in memory location 4
sw $t1, 0($sp) #save register $s0 for use in memory location 0
add $t0, $a0, $a1 #register $t0 contains $a0 + $a1
add $t1, $a2, $a3 #register $t1 contains $a2 + $a3
sub $s0, $t0, $t1 #$t0 = $t0 - $t1 -> $t0 = ($a0 + $a1) - ($a2 + $a3)
add $v0, $s0, $zero #copy $s0 to return register $v0
#Before returning, we restore three original values of registers we pushed onto stack by popping them
lw $t1, 0($sp) #restore register $s0 for caller
lw $t0, 4($sp) #restore register $t0 for caller
lw $s0, 8($sp) #restore register $t1 for caller
addi $sp, $sp, 12 #adjust stack to delete 3 items
jr $ra #jump back to calling routine
改进版。
.text
main:
addi $a0,$0,2 #argument 0 = 2
addi $a1,$0,3 #argument 1 = 3
addi $a2,$0,4 #argument 2 = 4
addi $a3,$0,5 #argument 3 = 5
jal leaf # call function leaf
add $s0,$v0,$zero # return value
li $v0,10
syscall
leaf:
addi $sp, $sp, -4 #adjust stack to make room for 3 items
sw $s0, 0($sp) #save register $t1 for use in memory location 8
add $t0, $a0, $a1 #register $t0 contains $a0 + $a1
add $t1, $a2, $a3 #register $t1 contains $a2 + $a3
sub $s0, $t0, $t1 #$t0 = $t0 - $t1 -> $t0 = ($a0 + $a1) - ($a2 + $a3)
add $v0, $s0, $0 #copy $s0 to return register $v0
#Before returning, we restore three
#original values of registers we pushed
#onto stack by popping them
lw $s0, 0($sp) #restore register $t1 for caller
addi $sp, $sp, 4 #adjust stack to delete 3 items
jr $ra #jump back to calling routine