在冒号后查找int（Python）

Question

我试图在冒号前后找到输入用户的整数值。我已经弄明白了如何检索第一个值，但如果冒号后面的值超过一个字符，它只会抓取第一个值。

startingWeight = input(("Starting weight of food (in lbs:ozs)="))
endingWeight = input(("Ending weight of food (in lbs:ozs="))

startingWeightPos = startingWeight.find(":")
endingWeightPos = endingWeight.find(":")

startingWeightPounds = startingWeight[0:startingWeightPos]
startingWeightOz = startingWeight[1:startingWeightPos]

endingWeightPounds = endingWeight[0:endingWeightPos]
endingWeightOz = endingWeight[1:endingWeightPos]

print (startingWeightPounds)
print (endingWeightPounds)
print (startingWeightOz)
print (endingWeightOz)

Answer 1

使用split获取:左侧和右侧的内容。

text = '100:66'
text_split = text.split(":")

lbs = text_split[0]
ozs = text_split[1]

如果需要，可以使用float()将它们转换为浮动。

Answer 2

如果您想使用切片，则两个切片为[:pos]（一切最高为pos），[pos+1:]（pos之后的所有内容）。

E.g。

pos = pounds.index(':')
pounds = weight[:pos]
oz = weight[pos+1:]

但split函数的存在使这更简单。

pounds, oz = weight.split(':')