Question

[09.02.2017 - 10:40:06][NOTICE] - Start looping through invoices from Teamleader..
[08.02.2017 - 10:24:26][NOTICE] - Start looping through invoices from Teamleader..
[08.02.2017 - 10:29:24][NOTICE] - Start looping through invoices from Teamleader..

这是产生上述输出的代码：

var data = allText.split("\n");
for(var i = 0, len = data.length; i < len; i++){
   console.log(data[i]);
}

是否可以在给定的日期和时间对数组进行排序？

以下是它应该如何显示的示例：

[09.02.2017 - 10:40:06][NOTICE] - Start looping through invoices from Teamleader..
[08.02.2017 - 10:29:25][NOTICE] - Start looping through invoices from Teamleader..
[08.02.2017 - 10:24:26][NOTICE] - Start looping through invoices from Teamleader..

Answer 1

在撰写本文时，其他解决方案要么不完整，要么包含错误。特别是，accepted answer by rakwaht将日期排序为字符串，这会产生不正确的结果。

您可以使用正则表达式和Date构造函数从行中提取和解析日期。从那里开始，只需要对包含这些行的数组进行排序：

＆＃13;

const data = `
[09.02.2017 - 10:40:06][NOTICE] - Start looping through invoices from Teamleader..
[08.02.2017 - 10:24:26][NOTICE] - Start looping through invoices from Teamleader..
[08.02.2017 - 10:29:24][NOTICE] - Start looping through invoices from Teamleader..`
  .trim().split('\n')

function dateFromLine(line) {
  const result = /^\[(.*?)\]/.exec(line)
  const date = result[1].replace("-", "")
  return new Date(date)
}

function compareLinesByDate(a, b) {
  return dateFromLine(b) - dateFromLine(a)
}

data.sort(compareLinesByDate)
console.log(data.join('\n'))

＆＃13;

请注意，此代码假定每行都以这种方式格式化。为了使其更加健壮，还需要做更多的工作。

Answer 2

您可以使用sort函数对数组进行排序，您可以在其中指定应对其进行排序的基数：

这是一个符合您需求的示例：

＆＃13;

var data = [
"[09.02.2017 - 10:40:06][NOTICE] - Start looping through invoices from Teamleader]",
"[08.02.2017 - 10:24:26][NOTICE] - Start looping through invoices from Teamleader]",
"[08.02.2017 - 10:29:24][NOTICE] - Start looping through invoices from Teamleader]"
];
data.sort(
    function(a, b){ 
         // a and b are two elements in the list that are supposed to be compared
         var a_date = a.substring(1, 22); //take only date from string
         var b_date = b.substring(1, 22); //take only date from string
         // We compare those strings to order it.
         if ( a_date < b_date )
            return 1;
         if ( a_date > b_date  )
            return -1;
         return 0;
    }
);
 console.log(data);

＆＃13;

YouTube Data API - Errors你可以在JS中找到对sort函数的一些引用

Answer 3

您可以使用数组中的函数sort()和比较函数来比较日期。我不知道你要比较什么，但这是一个简单的例子。

[/*...*/].sort(function(a, b){
    //here a and b stand for your dates. you will need to adjuste your code to  make it works since we have very little information about it.
    return Date.compare(a, b);
});

Answer 4

好吧，如果我必须这样做，我会在一个真实的数组中转换它然后使用这样的函数：

function SortByDate(a, b){
  var aDateField = a.DateField.toLowerCase();
  var bDateField = b.DateField.toLowerCase(); 
  return ((aDateField < bNDateField) ? -1 : ((aDateField > bDateField) ? 1 : 0));
}

var data = allText.split("\n");
for(var i = 0, len = data.length; i < len; i++){
   //construct your array_data here 
}
var dataSortByDate = array_data.sort(SortByDate);

这是我经常使用的比较功能之一。希望它会有所帮助。

JS：关于日期和时间的排序数组

4 个答案: