请在下面找到代码段。该实现读取excel表中特定列的单元格值。
459000.00等数字值正由代码读取为459000.00000000006。对于少数数字而言它工作正常，但对某些人来说是失败的。
try
{
String AmountColumn="C";
File FS = new File(FileLocation);
FileInputStream FileStream = new FileInputStream(FS);
XSSFWorkbook FileWorkbook = new XSSFWorkbook(FileStream);
Sheet FileWorksheet = FileWorkbook.getSheetAt(0);
double[] AmountArray = new double[FileWorksheet.getPhysicalNumberOfRows() - 1];
Iterator<Row> iterator2 = FileWorksheet.iterator();
int i2 = 0;
while (iterator2.hasNext())
{
if (i2 == 0)
{
iterator2.next();
}
else
{
AmountArray[i2 - 1] = iterator2.next().getCell(CellReference.convertColStringToIndex(AmountColumn)).getNumericCellValue();
System.out.println("Amount is: " + AmountArray[i2 - 1]);
}
i2++;
}
Amount = AmountArray;
}
catch (Exception e)
{
e.printStackTrace();
}
答案 0 :(得分：1)
Excel比Java更多地舍入结果。存储的真实值可能是459000.00000000006，但仍显示为459000.0
如果我将459000.00000000006输入Excel，则会显示459000
一个简单的解决方案是使用你得到的名字的一点点。
e.g。小数点后6位
/**
* Performs a round which is accurate to within 1 ulp. i.e. for values very close to 0.5 it
* might be rounded up or down. This is a pragmatic choice for performance reasons as it is
* assumed you are not working on the edge of the precision of double.
*
* @param d value to round
* @return rounded value
*/
public static double round6(double d) {
final double factor = 1e6;
return d > WHOLE_NUMBER / factor || d < -WHOLE_NUMBER / factor ? d :
(long) (d < 0 ? d * factor - 0.5 : d * factor + 0.5) / factor;
}