我知道如果队列已满,新任务将由新创建的线程按优先级执行How to guarantee FIFO execution order in a ThreadPoolExecutor
但我有以下测试代码片段,其中核心大小=最大核心大小。
public class ThreadPoolFifoTest {
public static void main(String[] args) throws InterruptedException {
Executor ex = Executors.newFixedThreadPool(10);
final List<Integer> l = new LinkedList<Integer>();
final ReentrantLock lock = new ReentrantLock(true);//fair lock
for(int i=0;i<10000;i++){
final int num = i ;
ex.execute(new Runnable() {//FIFO submit
@Override
public void run() {
//here since queue is FIFO, it is easy to consider that somebody should be take the task FIFO and let the thread to run this task
//so it easy to consider that this should be fifo to go to here.
//But as a result , it is not.
lock.lock();
l.add(num);
lock.unlock();
}
});
}
Thread.sleep(1000);
System.out.println(l);
List<Integer> sortedList= new LinkedList<Integer>(l);
Collections.sort(sortedList);
System.out.println(sortedList);
System.out.println(l.equals(sortedList));//not equals here
}
}
输出:
[0, 1, 2, 3, 4, 5, 6, 7, 8, 10, 11, 12, 9, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 85, 84, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99]
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99]
false
由于线程池下的队列是FIFO,任务应该是轮询FIFO并在线程中运行,所以因为我提交任务后续命令0.1.2.3.4 ..... 999,我的l
应该看起来像排序,但从输出,它不是,这是不是意味着执行顺序不是FIFO?为什么不?
如果我需要执行FIFO任务怎么办?
答案 0 :(得分:1)
问题是线程只按顺序关闭消息,但是独立运行(如线程所应)如果你想在FIFO中执行你应该
例如
List<Result> results = IntStream.range(0, 10000).parallel()
.mapToObject(i -> func(i))
.collect(Collector.toList());
这将允许并发执行,但结果将按原始顺序显示。
BTW当您对LinkedList进行排序时,必须将其转换为数组,对其进行排序并将其复制回链接列表。我建议使用一个可以按顺序排序的ArrayList。