我试图写一个函数,它可以返回" malloc"函数指针。
但是有一个错误,该平台是Windows 7 + Visual Studio 2015。
源代码" malloc.cpp":
#include <cstdlib>
namespace portable {
static void *(*malloc_impl)(size_t) = std::malloc;
static void (*free_impl)(void*) = std::free;
static void *(*realloc_impl)(void*, size_t) = std::realloc;
static void *(*calloc_impl)(size_t, size_t) = std::calloc;
#if defined(_WIN32) && defined(__MINGW32__)
# error("sorry, we don't support MinGW32 compiler with Windows")
#endif
#if defined(_WIN32) && defined(_MSC_VER)
# include <WinSock2.h>
# include <Windows.h>
static size_t (*malloc_usable_size_impl)(void*) = _msize;
#elif defined(__APPLE__)
# include <malloc.h>
static size_t (*malloc_usable_size_impl)(void*) = malloc_size;
#else
# include <malloc.h>
static size_t (*malloc_usable_size_impl)(void*) = malloc_usable_size;
#endif
void *( *o_set_malloc( void *(*func)(size_t) ) ) (size_t) throw()
{
void *(*old)(size_t) = malloc_impl;
if (func) {
malloc_impl = func;
}
return old;
}
size_t ( *o_set_malloc_usable_size( size_t (*func)(void*) ) ) (void*) throw()
{
size_t (*old)(void*) = malloc_usable_size_impl;
if (func) {
malloc_usable_size_impl = func;
}
return old;
}
void ( *o_set_free( void (*func)(void*) ) ) (void*) throw()
{
void (*old)(void*) = free_impl;
if (func) {
free_impl = func;
}
return old;
}
void *( *o_set_realloc( void *(*func)(void*, size_t) ) ) (void*, size_t) throw()
{
void *(*old)(void*, size_t) = realloc_impl;
if (func) {
realloc_impl = func;
}
return old;
}
void *( *o_set_calloc( void *(*func)(size_t, size_t) ) ) (size_t, size_t) throw()
{
void *(*old)(size_t, size_t) = calloc_impl;
if (func) {
calloc_impl = func;
}
return old;
}
}
编译器报告错误:
严重级代码描述项目文件行抑制状态 错误(活动)
不兼容的异常规范
d:\ work \ project \ orange \ src \ portable \ malloc.cpp 56
似乎&#34; old&#34;与返回类型不兼容。请帮帮我。
答案 0 :(得分:-1)
感谢评论,我发现了问题。
在Windows 7 + VS2015上,我定义了类似的内容:
#define NOEXCEPT throw()
不兼容的是“void *(*)(size_t)
”和“void *(*)(size_t) throw()
”。