Question

这就是我写的。我猜它可能是我的while循环的逻辑，但我无法发现它！任何帮助表示赞赏！谢谢。

#include <stdio.h>
#include <math.h>

//Open main function.
int main(void)
{
    double new_area, area_total = 14000, area_uncut = 2500, rate = 0.02, years;
    int count = 0;

    printf("This program is written for a plot of land totaling 14000 acres,    "
           "with 2500 acres of uncut forest\nand a reforestation rate "
           "of 0.02. Given a time period (years) this program will output a table\n"
           "displaying the number acres reforested at the end of "
           "each year.\n\n\n");

    printf("Please enter a value of 'years' to be used for the table.\n"
           "Values presented will represent the number acres reforested at the end of "
           "each year:>> ");

    scanf("%lf", &years);

    years = ceil(years);

    printf("\n\nNumber of Years\t\tReforested Area");

    while (count <= years);
    {
        count = count + 1;
        new_area = area_uncut + (rate * area_uncut);
        printf("\n%1.0lf\t\t\t%.1lf", count, area_uncut);
        area_uncut += new_area;
    }

    return 0;
}

Answer 1

此行末尾有一个额外的;：while (count <= years);

它被解析为while循环的空体，导致它永远迭代，因为count根本没有更新。

这是一种避免这种愚蠢错误的方法：使用Kernighan和Ritchie样式，{位于行的末尾，开始控制块：

while (count <= years) {
    count = count + 1;
    new_area = area_uncut + (rate * area_uncut);
    printf("\n%d\t\t\t%.1f", count, area_uncut);
    area_uncut += new_area;
}

使用这种风格，额外的;输入的可能性要小得多，并且更容易被发现为不协调。

另请注意，count定义为int，因此printf格式也不正确。绝对编译时启用了更多警告。

为什么我运行这个程序时会一直空着？

1 个答案: