Question

编写一个函数，创建一个名为“Points”的系列，这是一个加权值，其中每枚金牌（Gold.2）计3分，银牌（Silver.2）2分，青铜奖牌（Bronze.2）1分。该函数应仅返回您创建的列（Series对象）。

此函数应返回长度为146

的名为Points的系列

我是python和pandas的新手，我不知道我是否在正确的轨道上使用此代码，但我收到了一个关键错误

KeyError: "['Gold.2' 'Silver.2' 'Bronze.2'] not in index" for this code: 

import pandas as pd

df = pd.read_csv('olympics.csv', index_col=0, skiprows=1)

def answer_four():

    df['Points'] = df[(df[['Gold.2','Silver.2','Bronze.2']], [3,2,1])]
    #df[['Gold.2','Silver.2','Bronze.2']].apply(lambda x:(x,[3,2,1]))
    olympic_points_df = df[['Points']]


    return olympic_points_df

answer_four()

非常感谢任何帮助。

Answer 1

有些类似于此的技巧

def answer_four():
    df['Points'] = df['Gold.2']*3 + df['Silver.2']*2 + df['Bronze.2'] 
    return df['Points']

Answer 2

@PostMapping(path = "{make}",
  produces = MediaType.APPLICATION_JSON_VALUE,
  consumes = MediaType.APPLICATION_JSON_VALUE)
public RequestBody<Object> create(@PathVariable("make") String make,
                                 @org.springframework.web.bind.annotation.RequestBody RequestBody<Object> body) {
  // please change the name of "RequestBody" entity, in order to avoid name clash with the annotation
}

Answer 3

您可以先检查列名，然后在必要时进行一些重命名：

import pandas as pd

df = pd.read_csv('olympics.csv',
                 index_col=0,
                 skiprows=1
                )

for col in df.columns:
    if 'gold' in col.lower():
        print(col)
        # and maybe perform a rename if needed: 
        # df.rename(columns={col:'Gold'+'.2'},
        #           inplace=True)


def answer_four():
    df['Points'] = pd.Series((df['Gold.2']*3) + (df['Silver.2']*2) + df['Bronze.2'])
    return df['Points']


answer_four()

奥运奖牌积分系统，3金牌，2银奖，1铜奖

3 个答案: