Question

我必须在像这样的for循环中运行mysql查询

$date_start = '2017-01-01';
$date_end = '2017-01-10';
while ($date_start < $date_end){
   $sql ("SELECT id FROM mytable WHERE mydate = '$data_start'"); [<--edit]
   $result = $db->query($sql);
   $f = $result->fetch();
   echo 'result is : '.$f['id'];
   $date_start = date('Y-m-d', strtotime($date_start. ' + 1 days'));
}

ID结果始终与第一个$ date_start相关，然后是第一个sql查询......

如何等待php for mysql完成查询？

编辑：

好的，我在这里创建循环时出现了错误，但这是一种分心！这不是复制/粘贴

在此之后我写了

ID result was always related to first $date_start, then first sql query...

这意味着这不是代码问题，循环工作，否则我有一个php错误！

我将尝试使用MYSQL错误报告

Answer 1

您有一个未正确关闭的字符串文字，并且查询对变量$sql的分配不正确。因此脚本崩溃

// while testing specially if you are developing on a live server
// that will have error reporting to the screen turned off
// add these 4 lines so you see your errors on the browser page
ini_set('display_errors', 1); 
ini_set('log_errors',1); 
error_reporting(E_ALL); 
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);

$date_start = '2017-01-01';
$date_end = '2017-01-10';
while ($date_start < $date_end){
    $sql = "SELECT id FROM mytable WHERE mydate = '$data_start'";
    // --new character added to close the literal------------->^
    // () removed
    $result = $db->query($sql);
    // check for errors
    if ( !$result) {
        echo $result->error;
        exit;
    }
    $f = $result->fetch();
    echo 'result is : '.$f['id'];
    $date_start = date('Y-m-d', strtotime($date_start. ' + 1 days'));
}

PHP等待MYSQL完成查询

1 个答案: