Question

这是我的Spring Boot 1.5.1执行器application.properties：

#Spring Boot Actuator
management.contextPath: /actuator
management.security.roles=R_0

这是我的WebSecurityConfig：

@Configuration
@EnableWebSecurity
public class WebSecurityConfig extends WebSecurityConfigurerAdapter {

    @Autowired
    private UserDetailsService userDetailsService;

    @Value("${logout.success.url}")
    private String logoutSuccessUrl;

    @Override
    protected void configure(HttpSecurity http) throws Exception {

        // @formatter:off
        http.addFilterBefore(new CorsFilter(), ChannelProcessingFilter.class);

        http
            .csrf().ignoringAntMatchers("/v1.0/**", "/logout")
        .and()
            .authorizeRequests()

            .antMatchers("/oauth/authorize").authenticated()
            //Anyone can access the urls
            .antMatchers("/signin/**").permitAll()
            .antMatchers("/v1.0/**").permitAll()
            .antMatchers("/auth/**").permitAll()
            .antMatchers("/actuator/health").permitAll()
            .antMatchers("/actuator/**").hasAuthority("R_0")
            .antMatchers("/login").permitAll()
            .anyRequest().authenticated()
        .and()
            .formLogin()
                .loginPage("/login")
                .loginProcessingUrl("/login")
                .failureUrl("/login?error=true")
                .usernameParameter("username")
                .passwordParameter("password")
                .permitAll()
            .and()
                .logout()
                    .logoutUrl("/logout")
                    .logoutSuccessUrl(logoutSuccessUrl)
                    .permitAll();
        // @formatter:on
    }

    /**
     * Configures the authentication manager bean which processes authentication requests.
     */
    @Override
    protected void configure(AuthenticationManagerBuilder auth) throws Exception {
        auth.userDetailsService(userDetailsService).passwordEncoder(new BCryptPasswordEncoder());
    }

    @Override
    @Bean
    public AuthenticationManager authenticationManagerBean() throws Exception {
        return super.authenticationManagerBean();
    }

}

现在，我已成功登录我的应用程序，并拥有R_0权限的合适用户，但当我尝试访问时，

http://localhost:8080/api/actuator/beans

我收到以下错误：

There was an unexpected error (type=Forbidden, status=403).
Access is denied. User must have one of the these roles: R_0

如何正确配置Spring Boot Actuator以了解正确的Authentication？

现在为了让它工作，我必须做以下技巧：

management.security.enabled=false

.antMatchers("/actuator/health").permitAll()
.antMatchers("/actuator/**").hasAuthority("R_0")

是否有机会以正确的方式配置执行器？

已更新

我正在使用UserDetailsService.UserDetails.Authorities

    public Collection<? extends GrantedAuthority> getAuthorities() {
        String[] authorities = permissions.stream().map(p -> {
            return p.getName();
        }).toArray(String[]::new);
        return AuthorityUtils.createAuthorityList(authorities);
    }

Answer 1

您必须为ROLE_使用前缀management.security.roles，例如management.security.roles=ROLE_SOMENAME才能解决此问题

Answer 2

要获得弹簧启动执行器端点的授权，您需要具有 ACTUATOR 角色。请参阅此示例Accessing Restricted Actuator Endpoints with Spring Security

Answer 3

我来自Reactive Spring Boot 2.x应用程序，遇到了这个问题，并通过更新WebSecurityConfig.securityWebFilterChain以及SecurityContextRepository.load使其包含/ actuator / **来解决此问题，如下所示：

public class WebSecurityConfig {
  private AuthenticationManager authenticationManager;

  private SecurityContextRepository securityContextRepository;

  @Autowired
  public WebSecurityConfig(AuthenticationManager authenticationManager, SecurityContextRepository securityContextRepository) {
    this.authenticationManager = authenticationManager;
    this.securityContextRepository = securityContextRepository;
  }

  @Bean
  public SecurityWebFilterChain securityWebFilterChain(ServerHttpSecurity http) {
    return http
      .exceptionHandling()
      .authenticationEntryPoint((swe, e) -> Mono.fromRunnable(() -> {
        swe.getResponse().setStatusCode(HttpStatus.UNAUTHORIZED);
      })).accessDeniedHandler((swe, e) -> Mono.fromRunnable(() -> {
        swe.getResponse().setStatusCode(HttpStatus.FORBIDDEN);
      })).and()
      .csrf().disable()
      .formLogin().disable()
      .httpBasic().disable()
      .authenticationManager(authenticationManager)
      .securityContextRepository(securityContextRepository)
      .authorizeExchange()
      .pathMatchers("/actuator/**").permitAll()
      .anyExchange().authenticated()
      .and().build();
  }

以及更新

@Slf4j
@Component
public class SecurityContextRepository implements ServerSecurityContextRepository {

  private AuthenticationManager authenticationManager;

  public SecurityContextRepository(AuthenticationManager authenticationManager) {
    this.authenticationManager = authenticationManager;
  }

  @Override
  public Mono<Void> save(ServerWebExchange swe, SecurityContext sc) {
    return Mono.error(new UnsupportedOperationException("Not supported"));
  }

  @Override
  public Mono<SecurityContext> load(ServerWebExchange swe) {
    ServerHttpRequest request = swe.getRequest();

    if (request.getPath().value().startsWith("/actuator") ) {
      return Mono.empty();
    }
    // other authentication logic here
  }

Answer 4

1
1.You can add the following properties
endpoints.health.enabled=true
endpoints.loggers.enabled=true
endpoints.metrics.enabled=true

endpoints.env.enabled=false
endpoints.configprops.enabled=false
endpoints.autoconfig.enabled=false
endpoints.info.enabled=false

management.context-path=/management

2)
@Configuration
@EnableWebSecurity
public class WebSecurityConfig extends WebSecurityConfigurerAdapter implements ApplicationContextAware {

    private static final String ACTUATOR = "ACTUATOR";
    private static final String ROLE1 = "USER";

    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http.httpBasic().and().authorizeRequests().antMatchers("/controllerpath/**")
                .hasAnyRole(ROLE1).antMatchers("/loggers/**","/metrics/**","/health/**").hasAnyRole(ACTUATOR).and()

                .csrf().disable().headers().frameOptions().disable();

    }

    @Override
    protected void configure(AuthenticationManagerBuilder auth) throws Exception {

        auth.inMemoryAuthentication().passwordEncoder(new BCryptPasswordEncoder())
                .withUser("username-of-app").password("encryptedpassword")
                .roles(ROLE1).and().withUser("username-of-management-for-path")
                .password("encrypted password").roles(ACTUATOR);

    }
}

Answer 5

您可以添加以下属性

    endpoints.health.enabled=true
    endpoints.loggers.enabled=true
    endpoints.metrics.enabled=true
    
    endpoints.env.enabled=false
    endpoints.configprops.enabled=false
    endpoints.autoconfig.enabled=false
    endpoints.info.enabled=false
    
    management.context-path=/management

    @Configuration
    @EnableWebSecurity
    public class WebSecurityConfig extends WebSecurityConfigurerAdapter implements ApplicationContextAware {
    
        private static final String ACTUATOR = "ACTUATOR";
        private static final String ROLE1 = "USER";
    
        @Override
        protected void configure(HttpSecurity http) throws Exception {
            http.httpBasic().and().authorizeRequests().antMatchers("/controllerpath/**")
                    .hasAnyRole(ROLE1).antMatchers("/loggers/**","/metrics/**","/health/**").hasAnyRole(ACTUATOR).and()
    
                    .csrf().disable().headers().frameOptions().disable();
    
        }
    
        @Override
        protected void configure(AuthenticationManagerBuilder auth) throws Exception {
    
            auth.inMemoryAuthentication().passwordEncoder(new BCryptPasswordEncoder())
                    .withUser("username-of-app").password("encryptedpassword")
                    .roles(ROLE1).and().withUser("username-of-management-for-path")
                    .password("encrypted password").roles(ACTUATOR);
    
        }
    }

Answer 6

根据这个链接：

https://www.w3.org/TR/CSS21/visuren.html#float-rules

默认情况下，所有敏感HTTP端点都是安全的   具有ACTUATOR角色的用户可以访问它们。安全性得到执行   使用标准的HttpServletRequest.isUserInRole方法。

如果您需要，请使用management.security.roles属性   与ACTUATOR不同。

所以我认为您所要做的就是在application.properties中设置以下属性。

SystemStackError: stack level too deep

例如：

management.security.roles

Spring Boot Actuator Endpoints安全性不适用于自定义Spring Security配置

6 个答案: