Question

我有一个表名 tbl_marketing 包含许多列

DB_ID，db_customer，db_brand，db_client ....

另一个表名tbl_phonecall包含许多列，并与tbl_marketing中的db_mid相关联，其中包含tbl_marketing的 id

DB_ID，db_subject，db_due，db_nextdate，db_mid

知道我创建了一个搜索表单，这个搜索表单应该在tbl_marketing上的所有字段上搜索，并在用户进行搜索时在db_due和db_nextdate中搜索结果应该是这样的

客户品牌客户即将到期 来自tbl_marketing的客户品牌和客户以及来自tbl_phonecall

的其他客户品牌和客户

对于该搜索，我使用此php代码

$q = array();  
    $sql = "";
     if(isset($_POST['txt_name']) && !empty($_POST['txt_name'])){  
    $name = mysqli_real_escape_string($conn,$_POST['txt_name']); 
    $q[] = "tbl_marketing.db_customer='".$name."' ";      
    }
    if(isset($_POST['txt_client']) && !empty($_POST['txt_client'])){  
    $client = mysqli_real_escape_string($conn,$_POST['txt_client']); 
    $q[] = "tbl_marketing.db_client='".$client."' ";      
    }
    if(isset($_POST['txt_brand']) && !empty($_POST['txt_brand'])){  
    $brand = mysqli_real_escape_string($conn,$_POST['txt_brand']); 
    $q[] = "tbl_marketing.db_brand='".$brand."' ";      
    }
    if(isset($_POST['txt_dateofcalling']) && !empty($_POST['txt_dateofcalling'])){  
    $dateofcalling= mysqli_real_escape_string($conn,$_POST['txt_dateofcalling']);
    $searchdateofcalling=date("Y-m-d H:i:s", strtotime($dateofcalling));    
    $q[] = "DATE(tbl_phonecall.db_due)='".$searchdateofcalling."' ";      
    }
     if(isset($_POST['txt_nextdate']) && !empty($_POST['txt_nextdate'])){  
    $nextdate= mysqli_real_escape_string($conn,$_POST['txt_nextdate']);
    $searchnextdate=date("Y-m-d H:i:s", strtotime($nextdate));       
    $q[] = "DATE(tbl_phonecall.db_nextdate)='".$searchnextdate."' ";      
    }
    $first = true; 
    foreach($q as $qu){  
        if($first){  
        $sql .= " where ".$qu;      
        $first = false;  
        }else{  
        $sql .= " and ".$qu;          
        } 
    } 
$query=mysqli_query($conn,"select tbl_marketing.*,tbl_phonecall.* from tbl_marketing,tbl_phonecall {$sql}")or die(mysqli_error($conn));

但此查询会重复值

我如何解决这个问题并得到像我之前发布的结果

Answer 1

看起来你错过了加入条件

where tbl_marketing.db_id = tbl_phonecall.db_mid

如果您想要从tbl_phoneeting返回记录，即使tbl_phonecall表中不存在匹配的记录，请在查询中使用左连接

select tbl_marketing.*,tbl_phonecall.* 
from tbl_marketing left join tbl_phonecall 
on tbl_marketing.id = tbl_phonecall.mid 
where ....<<where conditions here>>

Mysql在两个表中搜索

1 个答案: