Question

class SomewebsiteProductSpider(scrapy.Spider):
    name = "somewebsite"
    allowed_domains = ["somewebsite.com"]


start_urls = [

]

def parse(self, response):
    items = somewebsiteItem()

    title = response.xpath('//h1[@id="title"]/span/text()').extract()
    sale_price = response.xpath('//span[contains(@id,"ourprice") or contains(@id,"saleprice")]/text()').extract()
    category = response.xpath('//a[@class="a-link-normal a-color-tertiary"]/text()').extract()
    availability = response.xpath('//div[@id="availability"]//text()').extract()
    items['product_name'] = ''.join(title).strip()
    items['product_sale_price'] = ''.join(sale_price).strip()
    items['product_category'] = ','.join(map(lambda x: x.strip(), category)).strip()
    items['product_availability'] = ''.join(availability).strip()
    fo = open("C:\\Users\\user1\PycharmProjects\\test.txt", "w")
    fo.write("%s \n%s \n%s" % (items['product_name'], items['product_sale_price'], self.start_urls))
    fo.close()
    print(items)
    yield items

test.py

process = CrawlerProcess({
            'USER_AGENT': 'Mozilla/4.0 (compatible; MSIE 7.0; Windows NT 5.1)'
        })

        process.crawl(SomewebsiteProductSpider)
        process.start()

如何将动态start_urls列表传递给＆＃34; SomewebsiteProductSpiders＆＃34;启动爬网过程之前来自test.py的对象？任何帮助，将不胜感激。谢谢。

Answer 1

process.crawl接受传递给spider的构造函数的可选参数，因此您可以从spider start_urls填充__init__或使用自定义start_requests程序。例如

<强> test.py

...
process.crawl(SomewebsiteProductSpider, url_list=[...])

<强> somespider.py

class SomewebsiteProductSpider(scrapy.Spider):
    ...
    def __init__(self, *args, **kwargs):
        self.start_urls = kwargs.pop('url_list', [])
        super(SomewebsiteProductSpider, *args, **kwargs)

Answer 2

只需将start_urls作为参数，您就可以避免从@mizghun的答案中解析出额外的kwarg。

import scrapy
from scrapy.crawler import CrawlerProcess

class QuotesSpider(scrapy.Spider):
  name = 'quotes'

  def parse(self, response):
    print(response.url)

 process = CrawlerProcess()
 process.crawl(QuotesSpider, start_urls=["http://example.com", "http://example.org"])
 process.start()

使用scrapy进行爬网时动态启动网址列表

2 个答案: