Question

我有一个字符串，如下所示，

让newString : String = "12","34","56","78","910","1112","1314","1516","1718","1920","2122","2324","2526","2729".

我想将字符串与"4 string each"字符串分开，例如"12","34","56","78" and "910","1112","1314","1516"等等。

我们可以通过使用范围或其他东西实现这一目标吗？

注意： - newString不是来自webservice的静态数据

Answer 1

您可以这样尝试，首先从String创建数组，然后从中创建块数组，然后从数组中加入字符串。

let newString = "1,2,3,4,5,6,7,8,9,10,11,12"
let array = newString.components(separatedBy: ",") // ["1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12"]
let chunkSize = 4
let chunksArray = stride(from: 0, to: array.count, by: chunkSize).map {
    Array(array[$0..<min($0 + chunkSize, array.count)])
}
let subArray = chunksArray.map { $0.joined(separator: ",") }
// ["1,2,3,4", "5,6,7,8", "9,10,11,12"]

编辑：您可以像这样合并最后两个动作。

let subArray = stride(from: 0, to: array.count, by: chunkSize).map { 
    array[$0..<min($0 + chunkSize, array.count)].joined(separator: ",") 
}
// ["1,2,3,4", "5,6,7,8", "9,10,11,12"]

Answer 2

首先从字符串生成一个数组：

let newString = "1,2,3,4,1234,1235,1236,1238,678,679"    
let newStringArray = newString.componentsSeparatedByString(",")

然后运行for循环并使用joinWithSeparator

添加字符串

Answer 3

您可以将,字符串拆分为：let strArr = newString.components(separatedBy: ",")，然后将strArr拆分为包含4个元素的数组，并按,加入每个结果数组。希望这有帮助，祝你好运！

将字符串拆分为子字符串，其中组件由字符串swift分隔

3 个答案: