目标:用c ++编写程序
1.Declare变量:double类型之一,String类型之一。
2.将双变量的总和打印到新行的小数点后一位。
3.将您读取的字符串与输入结合,并在新行上打印结果。 (完成此计划)
int main()
{
double d = 4.0;
string s = "hello and welcome ";
//write ur code here
// double variable
//string variable
//i/p double from user
// i/p string from user
// print sum of double
// print concatenated string
}
样本i / p = --- 4 umang mahant!
样本o / p ---- 8 你好,欢迎umang mahant!
//this is my code but it isnt taking the line as input i really dont know why?
#include <iostream>
#include <iomanip>
#include <limits>
using namespace std;
int main() {
double d = 4.0;
string s = "hello and welcome ";
double b;
string s2;
cin>>b;
getline(cin, s2, '\n');
cout<<d+b<<"\n";
cout<<s<<s2<<"\n";
}
答案 0 :(得分:1)
首先将s更改为
s = "hello and welcome"
然后看看下面的代码
#include <strtk.hpp>
double sum = d + b ; // adding doubles
std::string sum_as_string = strtk::type_to_string<double>(sum); //converted sum to string
std::string final_string = sum_as_string + s2 + s;//concatenate your input string to sum string and s string
现在打印final_string。
(你没有真正地连接字符串,将它们打印在一起不是解决方案!)
在getline(cin, s2)
插入此代码并删除两个cout语句后,最后写入
cout<<final_string<<"\n";
如果您不想在实际中连接字符串,那么您只需更正输入函数getline
。
回答您的黑客挑战
int p;
double q;
string s2,result;
// Declare second integer, double, and String variables.
// Read and save an integer, double, and String to your variables.
cin>>p;
cin>>q;
getline(cin >> ws ,s2);
// Note: If you have trouble reading the entire string, please go back and review the Tutorial closely.
// Print the sum of both integer variables on a new line.
cout<<p+i<<"\n";
// Print the sum of the double variables on a new line.
std::cout << std::fixed;
std::cout << std::setprecision(1);
cout<<q+d<<"\n";
// Concatenate and print the String variables on a new line
result = s + s2;
cout<<result<<"\n";
答案 1 :(得分:0)
我假设您在样本输入和输出下方发布的代码是您要询问的代码。
问题在于你的getline()函数。你为什么在这个函数中有3个参数?它会产生错误。您应该将getline()语句更改为:
getline(cin, s2);
这消除了错误,您的代码可以正常工作。