如何在java脚本中更改弹出标题?

时间:2017-02-09 11:44:57

标签: javascript jquery push-notification notifications service-worker

你能否告诉我如何更改弹出标题 ..目前显示http:\\s.codepen.io我们可以更改此网址吗?

http://codepen.io/anon/pen/WRaZOq

function notifyMe() {
  // Let's check if the browser supports notifications
  if (!("Notification" in window)) {
    alert("This browser does not support desktop notification");
  }

  // Let's check whether notification permissions have already been granted
  else if (Notification.permission === "granted") {
    // If it's okay let's create a notification
    var notification = new Notification("Hi there!");
  }

  // Otherwise, we need to ask the user for permission
  else if (Notification.permission !== 'denied') {
    Notification.requestPermission(function (permission) {
      // If the user accepts, let's create a notification
      if (permission === "granted") {
        var notification = new Notification("Hi there!");
      }
    });
  }

  // At last, if the user has denied notifications, and you 
  // want to be respectful there is no need to bother them any more.
}Notification.requestPermission().then(function(result) {
  console.log(result);
});function spawnNotification(theBody,theIcon,theTitle) {
  var options = {
      icon: theIcon
  }
  var n = new Notification(theTitle,options);
}

1 个答案:

答案 0 :(得分:1)

您需要查看通知constructor

第一个arg。是标题和第二个arg。是一个对象,指定其他详细信息,包括消息的 body 。所以你需要这样的东西

var notification = new Notification("the title",{body:"body of the notification"});