请帮助解决这个问题,独立查询如何工作,但下面的代码比较失败,我试图只比较日期而不是时间,所以尝试了这样的查询。
SELECT CAST(getdate() AS DATE)---'2/9/2017 12:00:00 AM'
SELECT CAST('2017/01/15' AS DATE)----'1/15/2017 12:00:00 AM'
SELECT CAST(getdate() AS DATE) > CAST('2017/01/15' AS DATE); -- Error SQLSTATE 42000
答案 0 :(得分:2)
您需要将此条件置于上下文中。比如像这样
SELECT case when CAST(getdate() AS DATE) > CAST('2017/01/15' AS DATE)
then 1
else 0
end
答案 1 :(得分:1)
您可以尝试使用DATEDIFF()找出2个日期之间的差异。
选择DATEDIFF(DAY,(CAST(' 2017/01/15' AS DATE)),(CAST(getdate()AS DATE)))
答案 2 :(得分:1)
尝试这样的事情:
DECLARE @nowDate DATE
SELECT @nowDate = CAST(getdate() AS DATE)
DECLARE @otherDate DATE
SELECT @otherDate = CAST('2017/01/15' AS DATE)
SELECT DATEDIFF(DAY, @nowDate, @otherDate)
答案 3 :(得分:1)
$words = array("arif", "arin", "asif", "armin", "arpan");
$pattern = '|^ar|';
$indices = array();
foreach ($words as $i => $word) {
// if there is a match
if (preg_match($pattern, $word)) {
// append the current index to the indices array
$indices[] = $i;
}
}
答案 4 :(得分:1)
您无法在READ_PHONE_STATE
中进行比较,您可以使用以下代码来确定日期是否大于当前日期,或者今天是。
SELECT