Question

如何查找范围之间的数字？

c = array[2,3,4,5,6]
>>> c>3
>>> array([False, False, True, True, True]

但是，当我在两个数字之间给出c时，它会返回错误

>>> 2<c<5
>>> ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()

欲望输出是

array([False, True, True, False, False]

Answer 1

试试这个，

(c > 2) & (c < 5)

<强>结果

array([False,  True,  True, False, False], dtype=bool)

Answer 2

Python将(2<c) and (c<5)评估为有效and，除了and关键字不能像numpy数组那样工作。（它尝试将每个数组转换为单个布尔值，并且不能覆盖该行为，如所讨论的here。）因此，对于具有numpy数组的向量化(2<c) & (c<5)操作，您需要这样做：< / p>

Just Get Row and its first parameter is your id and pass it into your deleteclick function { 'data': null, 'render': function (data, type, row) { var id = row.id; return '<button id="' + row.id + '" class="dodo" onclick="deleteClick("' + id + '")">Delete</button>' } } function deleteClick(var id) { alert(id); }

Answer 3

您可以这样做：

import numpy as np
c = np.array([2,3,4,5,6])
output = [(i and j) for i, j in zip(c>2, c<5)]

输出：

[False, True, True, False, False]

Python：numpy数组大于且小于值

3 个答案: