Question

js上的新内容，代码如下。在这里，我无法打印出正确的结果。我认为+ "names[i]"这部分代码存在问题。

var names = ["aha","mk", "jk","hk","fhf"];
for (i=1;i<=names.length;i++){
    console.log("I know someone called "+ "names[i]");
    }

Answer 1

请勿在引号names[i]中使用expression来提供您的价值

您可以使用es6模板字符串

var names = ["aha","mk", "jk","hk","fhf"];
   for (i=0;i<=names.length-1;i++){
       console.log(`I know someone called ${names[i]}`);
    }

Answer 2

var names = ["aha","mk", "jk","hk","fhf"];
for (i=1;i<=names.length;i++){
    console.log("I know someone called "+ names[i]);
    }

names [i]已经是一个字符串。

Answer 3

忽略名称[i]周围的引号。它应该是：

var names = ["aha","mk", "jk","hk","fhf"];
for (i=1;i<=names.length;i++){
    console.log("I know someone called "+ names[i]);
}

Answer 4

请检查名称[i]是否应该保留双引号并将i值更改为0

 var names = ["aha","mk", "jk","hk","fhf"];
 for (i=0;i<=names.length;i++)
 {
      console.log("I know someone called "+ names[i]);
 }

Answer 5

第一：就像所有人一直在说的那样，你不要将names[i]置于双引号内，因为它是对已定义变量的引用。
第二次：** ** for循环中的**声明为i<=names.length，但应为i<names.length。你的方式会一直走到6，这太高了。
THIRD ：除了第二个错误之外，您还必须将names[i]更改为names[i--]，因为i<names.length仍会达到5，而且也是很高的数字开头。

Answer 6

我认为这是正常的你需要删除=符号并设置i = 0

var names = ["aha","mk", "jk","hk","fhf"];
        for (i=0;i<names.length;i++){
        console.log("I know someone called "+ names[i]);
    }