Question

更新：我已尝试提取我想要更新的路径，并在setpath（路径; getpath（路径））构造中使用相对于本地和返回对象（如下所示）的路径。我现在可以遍历$ paths数组并对本地json对象进行所需的更新。

使用下面的thermostats2.json文件和一个与thermostats2.json不同的ret.json：

{“location”：{“livingroom”：{“setpoints”：{“day”：“25000”}}}} #vs {“day”：“23000”}

我的脚本现在看起来像：

. as $obj |

# obtain location keys from $obj as they may have changed locally prior to $retobj being processed

($obj.location | keys? ) as $locs |

# setpoints are fixed in this code as ["day","night","away"]

["day","night","away"] as $setpoints |

[path($obj.location[($locs[])].setpoints[($setpoints[])])] as $paths |

reduce
  range(0; $paths|length) as $i
(.; . | setpath($paths[$i];( $retobj[0] | getpath($paths[$i])))  ) | .

此时我不需要$ obj变量，但我还没有清理过它。如果您发现此方法存在问题或者这看起来是一个很好的解决方案，请发表评论。如果评论表明它应该是，我会回答这个问题。

我有一个json对象，它包含多个位置对象，每个位置对象包含几个设定点对象，以及其他数据。如果需要，将为此json对象提供远程应用程序，并将更新返回给设定点对象的值。我想更新本地json对象，而不是用返回的对象替换它。

我不想假设返回对象的位置键与本地对象的位置键相同，因为在修改远程对象时可能已经维护了本地对象。

我已经想出如何从本地文件中提取位置键，并创建一个包含我感兴趣的值更新的设定值键的数组。我还能够弄清楚如何将返回对象的更新值减少为数组。

我还没想到的是如何迭代位置和设定点以便更新本地json对象中的值。

我用：

调用jq

# usage : jq --slurpfile retobj ret.json --from-file query.jq thermostats2.json

query.jq contains:
# use $obj as the local object to be updated with values returned in $retobj
# $retobj is not permitted to modify the structure of $obj

. as $obj |

# obtain location keys from $obj as they may have changed locally prior to $retobj being processed

($obj.location | keys? ) as $locs |

# setpoints are fixed in this code as ["day","night","away"]

["day","night","away"] as $setpoints |
reduce $retobj[0].location[($locs[])].setpoints[($setpoints[])] as $item
( []; . + [$item] )
 | . as $vals |
$vals

thermostats2.json：

{ "mode":"Home",
  "location": {
    "livingroom": {
    "scale":"Celcius",
    "current": {
        "valid":"YES",
        "reading":"23000",
        "time":"000000"
    },
    "previous": {
        "reading":"23000",
        "time":"000000"
    },
    "setpoints": {
        "schedule": {
        "weekday": {"day":"0600",
                "night":"2100"
               },
        "weekend": {"day":"0630",
                "night":"2200"
               }
        },
        "active":"day",
        "day":"23000",
        "night":"15556",
        "away":"12778"
    }
    },
    "familyroom": {
    "scale":"Celcius",
    "current": {
        "valid":"YES",
        "reading":"23000",
        "time":"000000"
    },
    "previous": {
        "reading":"23000",
        "time":"000000"
    },
    "setpoints": {
        "schedule": {
        "weekday": {"day":"0600",
                "night":"2100"
               },
        "weekend": {"day":"0630",
                "night":"2200"
               }

        },
        "active":"day",
        "day":"23000",
        "night":"15556",
        "away":"12778"
    }
    },
    "28-000005e2fdef": {
    "scale":"Celcius",
    "current": {
        "valid":"YES",
        "reading":"23000",
        "time":"000000"
    },
    "previous": {
        "reading":"23000",
        "time":"000000"
    },
    "setpoints": {
        "schedule": {
        "weekday": {"day":"0600",
                "night":"2100"
               },
        "weekend": {"day":"0630",
                "night":"2200"
               }
        },
        "active":"day",
        "day":"23000",
        "night":"15556",
        "away":"12778"
    }
    }
  }
}

我找不到的是在$ obj中设置相同对象的值的任何方法，即有效：

$ obj [0] .location [（$ locs []）]。setpoints [（$ setpoints []）] = $ vals

据我所知，作为新手，我不太可能选择解决此类问题的首选方法。我也在努力在一些内置函数中使用过滤器范例，特别是foreach。

回顾我的目标，我希望：

通过从本地obj派生的位置键和过滤器中定义的设定点键在$ retobj中获取正确的对象值，并将本地对象中的相同路径设置为这些值。

Answer 1

基于我对这个问题的理解，我相信使用--argfile而不是--slurpfile可以简化事情。

以下过滤器将根据thermostats2.json的内容调整$ retobj：

. as $in
| reduce ["location",
          (.location | keys[]),
          "setpoints",
          ["day","night","away"][]] as $path
    ( $retobj;
      setpath( $path; ($in | getpath($path)) ) )

调用： jq --argfile retobj ret.json -f query.jq thermostats2.json

jq试图迭代两组值

1 个答案: