TypeError：__ init __（）得到了一个意外的关键字参数'method'

Question

好吧，我正在写一个烧瓶项目，但当我尝试python manage.py时
追溯告诉我：

Traceback (most recent call last):
  File "manage.py", line 5, in <module>
    from app import db,create_app
  File "/home/humbert/2017-sharing-backend/sharing/app/__init__.py", line 42, in <module>
    app.register_blueprint(main_blueprint, url_prefix='/main')
  File "/home/humbert/venv/local/lib/python2.7/site-packages/flask/app.py", line 64, in wrapper_func
    return f(self, *args, **kwargs)
  File "/home/humbert/venv/local/lib/python2.7/site-packages/flask/app.py", line 951, in register_blueprint
    blueprint.register(self, options, first_registration)
  File "/home/humbert/venv/local/lib/python2.7/site-packages/flask/blueprints.py", line 154, in register
    deferred(state)
  File "/home/humbert/venv/local/lib/python2.7/site-packages/flask/blueprints.py", line 173, in <lambda>
    s.add_url_rule(rule, endpoint, view_func, **options))
  File "/home/humbert/venv/local/lib/python2.7/site-packages/flask/blueprints.py", line 76, in add_url_rule
    view_func, defaults=defaults, **options)
  File "/home/humbert/venv/local/lib/python2.7/site-packages/flask/app.py", line 64, in wrapper_func
    return f(self, *args, **kwargs)
  File "/home/humbert/venv/local/lib/python2.7/site-packages/flask/app.py", line 1043, in add_url_rule
    rule = self.url_rule_class(rule, methods=methods, **options)
TypeError: __init__() got an unexpected keyword argument 'method'

我认为我的manage.py是对的，我无法弄清楚错误。
__init__.py的错误部分是：

from .main import main as main_blueprint
app.register_blueprint(main_blueprint, url_prefix='/main')

from .auth import auth as auth_blueprint
app.register_blueprint(auth_blueprint, url_prefix="/auth")

from . import views

我真的需要一些帮助，谢谢！

Answer 1

我有类似的问题。在我的代码中，我有一行 @bp.route('/<init:id>/delete', method=('POST')) 关键字method需要更改为methods（带有s）

Answer 2

我在代码中遇到了类似的问题，只需要将关键字“ 方法”更改为“ 方法”：

@app.route('/login', methods = ['GET', 'POST'])