我试图为每个页面提供以下模型,以便我可以检查当前用户是否已登录,从而控制每个页面的标题菜单项,但我不想总是回报指数。有没有办法让自己回归?
@RequestMapping(value = "/**", method = RequestMethod.GET)
String index(Model model) {
Users user = usersRepository.findOne(1 L);
if (user != null) {
String currentRole = user.getRole().toString();
model.addAttribute("currentRole", currentRole);
// System.out.println("Current Role: " + currentRole);
} else {
model.addAttribute("currentRole", "ANONYMOUS");
}
return "index";
}
我的菜单:
<li th:switch="${currentRole}">
<!-- Is Employee, so show "My Requests" -->
<div th:case="EMPLOYEE">
<a href="#" th:href="@{/requests}">
<div style="float: left; margin-right: 10px;">My Requests</div>
<!-- Handle notifications here -->
<div style="overflow: hidden" id="circle">1</div>
</a>
</div>
<!-- Is Manager, so show "My Approvals" -->
<div th:case="MANAGER">
<a href="#" th:href="@{/requests}">
<div style="float: left; margin-right: 10px;">My Approvals</div>
<!-- Handle notifications here -->
<div style="overflow: hidden" id="circle">1</div>
</a>
</div>
</li>
<li><a href="#" th:href="@{/team}">My Team</a></li>
<!-- Is logged in, so don't show "Log In" -->
<li th:unless="${currentRole}">
<a href="/login" th:href="@{/login}" class="btn-login">Log In</a>
</li>
</ul>
答案 0 :(得分:3)
如果您使用的是Spring安全性,Thymeleaf有一个集成模块可以直接在您的模板中处理这个问题,因此您可能甚至不需要模型中的用户名。将依赖项添加到org.thymeleaf.extras:thymeleaf-extras-springsecurity4
的相应版本。
然后将xmlns添加到你的html
<html xmlns:th="http://www.thymeleaf.org"
xmlns:sec="http://www.thymeleaf.org/thymeleaf-extras-springsecurity4">
你可以做到
<div th:text="${#authentication.name}">
The value of the "name" property of the authentication object should appear here.
</div>
的更多信息
答案 1 :(得分:2)
当你使用Spring
时,你可以创建@ControllerAdvice
类并放置所需的逻辑,就像这样(未经测试)
@ControllerAdvice
public class UserRoleAdvice {
// ... autowire needed services
@ModelAttribute("currentRole")
public String currentRole() {
Users user = usersRepository.findOne(1 L);
if (user != null) {
return user.getRole().toString();
} else {
return "EMPLOYEE";
}
}
}
这将为所有页面添加此参数...